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2 years ago

Y=(x+1)^2+2plot five points

Mathematics

1 answer:

Stella [2.4K]2 years ago

6 0

Answer:

(−3,6)

(−2,3)

(−1.2)

(0,3)

(1,6)

Step-by-step explanation:

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In studies for a medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.

timofeeve [1]

Part a)

It was given that 3% of patients gained weight as a side effect.

This means

$p = 0.03$

$q = 1 - 0.03 = 0.97$

The mean is

$\mu = np$

$\mu = 643 \times 0.03 = 19.29$

The standard deviation is

$\sigma = \sqrt{npq}$

$\sigma = \sqrt{643 \times 0.03 \times 0.97}$

$\sigma =4.33$

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

$P(23.5 \: < \: X \: < \: 24.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \: \frac{24.5 - 19.29}{4.33} ) \\ = P( 0.97\: < \: z \: < \: 1.20) \\ = 0.051$

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.

P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

$P(X \: < \: 24.5) = P(z \: < \: \frac{24.5 - 19.29}{4.33} ) \\ = P(z \: < \: 1.20) \\ = 0.8849$

Part c)

We want to find the probability that

11 or more patients will gain weight as a side effect.

P(X≥11)

Apply correction factor to get:

P(X>11-0.5)=P(X>10.5)

We convert to z-scores:

$P(X \: > \: 10.5) = P(z \: > \: \frac{10.5 - 19.29}{4.33} ) \\ = P(z \: > \: - 2.03)$

$= 0.9788$

Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

$P(23.5 \: < \: X \: < \: 28.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \: \frac{28.5 - 19.29}{4.33} ) \\ = P( 0.97\: < \: z \: < \: 2.13) \\ = 0.1494$

3 0

3 years ago

SOMEONE HELP ME PLZZZZZZZ

Tamiku [17]

Answer:

59400

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Which statement is true? A.27/19<11/30 B.17/31>19/14 C.16/26>30/31 D.35/30<22/12

Mrac [35]

A. $\frac{27}{19}$

To find greater than or smaller than relation, we multiply the terms like (numerator of L.H.S with denominator of R.H.S and put the value on the left side. Then multiply the denominator of L.H.S with numerator of R.H.S and put the value on right side. Now compare the digits.)

So, solving A, we get 810<209 ... This is false

B. $\frac{17}{31}>\frac{19}{14}$

= 238>589 ..... This is false

C. $\frac{16}{26}>\frac{30}{31}$

= 496>780 .... This is false

D. $\frac{35}{30}$

= 420<660 ..... This is true

Hence, option D is true.

6 0

3 years ago

Martina earns $480 per week plus 15% commission on all of her sales. which shows the amount she earns each week as a function of

asambeis [7]

Answer:

The answer is B

Step-by-step explanation:

You have to add the 480 dollars which eliminates A and C. Then, when finding commission you make the commission rate into decimal form which eliminates D. Your only option left is B

5 0

3 years ago

WILL DO BRAINLIEST!!!! Suppose the store wants to earn a daily profit of $150 from the sale of soccer balls. To earn this profit

lara [203]

Think about it this way, what is 5x3??? 15 right. Ok then what is 5x30???? 150. So the store should sell each soccer ball for $5 each:)

6 0

3 years ago

Read 2 more answers

Y=(x+1)^2+2plot five points​

Y=(x+1)^2+2plot five points