1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vladimir1956 [14]
4 years ago
14

Resolve 36x2 – 81y2 into factors

Mathematics
1 answer:
Rom4ik [11]4 years ago
3 0

Answer:

(6x + 9y)(6x - 9y)

Step-by-step explanation:

We can use the difference of squares which states that a² - b² = (a + b)(a - b), in this case, a = 6x and b = 9y so the answer is (6x + 9y)(6x - 9y).

You might be interested in
I need help with this​
Schach [20]
8- 1/3 quarts
4- 2/3 quarts
7 0
3 years ago
Hi can u help please thanks
faltersainse [42]

The first one is the answer/

8 0
3 years ago
Help plz. i would greatly appreciate it​
vekshin1

Answer:

1) 5^2=25

2) 5^2=x

3) b^3=64

Step-by-step explanation:

To write logs of the form log_ba=x in their exponential form, you take the base b and put it to the power of x and then set that equal to a: b^x=a.

1. Here, b = 5, a = 25, and x = 2, so: 5^2=25

2. In this problem, b = 5, x = 2, and a = x, so: 5^2=x

3. Finally, here, b = b, a = 64, and x = 3, so: b^3=64

Hope this helps!

6 0
3 years ago
Read 2 more answers
Lines L and M are parallel. Lines t^1 and t^2 are transversals. What is m<1 if m<4=65*? Justify your answer. (Ps- there is
Diano4ka-milaya [45]
The complete question in the attached figure

we know that
m∡4=65°
m∡4=m∡2---------> by internal alternate angles
m∡5=m∡3---------> by internal alternate angles

m∡1=180°-m∡2---------> 180°-65°--------> m∡1=115°

the answer is 
m∡1=115°

3 0
3 years ago
Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi
Leona [35]

Answer:

The general solution of   cos x = cos(\frac{\pi }{6})   is  

                                                x = 2nπ±\frac{\pi }{6}

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Step-by-step explanation:

Explanation:-

Given equation is  

                              2cosx-\sqrt{3} =0  for 0

                              2cosx =\sqrt{3}

Dividing '2' on both sides, we get

                             cos x =\frac{\sqrt{3} }{2}

                             cos x = cos(\frac{\pi }{6})

<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of   </em>cos x = cos(\frac{\pi }{6})<em>   is  </em>

<em>                                                 x = 2nπ±</em>\frac{\pi }{6}<em></em>

put n=0

x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Put n=1  

x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}

x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}

put n=2

x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}

x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}

And so on

But given 0 < x< 2π

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

                               

6 0
3 years ago
Other questions:
  • Wright a variable expression for the word phrase, "the product of a number z and 7" A: 7 - z
    6·1 answer
  • Natalie and her friends decided to rent 4 learned at regular cost for a party.Ten people need to rent shoes,and 4 people are mem
    14·1 answer
  • Matty needs 200 buttons. Amy gives her 13 bags with 10 buttons in each bag. How many buttons does she need now
    10·1 answer
  • The number 15, 56 rounded to the nearest thousand is 15,000
    11·1 answer
  • Angles 1 and 5 are what type of angle pair?
    9·2 answers
  • A circular target is divided into four rings that have equal areas. If the radius of the target is 24cm, find the radius of the
    9·1 answer
  • Find the number of bricks to be laid in a square path of side 18cm if the side of each square bricks is 3cm
    8·1 answer
  • 5,256 divide 52 and show your work
    6·1 answer
  • Please help! WILL GIVE BRAINLIEST!!
    8·1 answer
  • 5x²-4(x²+1)<br>how to factorise this?​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!