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siniylev [52]
3 years ago
7

Nathan took his car in for service and repairs. He had a coupon for 10% off.

Mathematics
1 answer:
Olin [163]3 years ago
5 0
The answer would be $713.23
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A pom-pom manufacturer makes each of its pom-poms with 35% white strands (w), 25% blue strands (b), and 40% red strands (r). If
DIA [1.3K]

Answer:

28 white strands , 20 blue strands and 32 red strands are needed to make a pair of pom-poms

Step-by-step explanation:

Given :A pom-pom manufacturer makes each of its pom-poms with 35% white strands (w), 25% blue strands (b), and 40% red strands (r).

To Find : If each pom-pom has a total of 80 strands, how many of strands of each color are needed to make a pair of pom-poms?

Solution:

Total Strands = 80

White Strands = 35%

No. of white strands = 35\% \times 80 =\frac{35}{100} \times 80 =28

Blue Strands = 25%

No. of blue strands = 25\% \times 80 =\frac{25}{100} \times 80 =20

Red Strands = 40%

No. of Red strands = 40\% \times 80 =\frac{40}{100} \times 80 =32

Hence 28 white strands , 20 blue strands and 32 red strands are needed to make a pair of pom-poms

3 0
3 years ago
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A red gumball is 2 5/8 Inches across. A green gumball is 2 5/6 inches across and a blue gumball in 2 7/9 inches across. list the
Masteriza [31]

Answer: 5 8 7 9 5 6

Step-by-step explanation:

Because you go by which is closer to the denominator

8 0
3 years ago
What is the square root of 100?
natulia [17]

Answer:

10

Step-by-step explanation:

the answer is 10 because 100 divided by 10 is 10

Please mark Brainliest

3 0
2 years ago
Read 2 more answers
Tom has 15 pencils. 5 of them do not have erasers. which ratio compares the number of pencils without erasers to the number of p
Ipatiy [6.2K]
B. 5:10 because 15-5=10 which is the number of pencils with erasers and the 5 left are the amount of pencils which are missing an eraser
6 0
3 years ago
Define z_alpha to be a z-score with an area of alpha to the right. For Example: z_0.10 means P(Z > z_0.10) = 0.10. We would a
Reptile [31]

Answer:

a) P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

And for this case the two values are :z_{crit}= \pm 1.96

b) P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

c) For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

And for this case the two values are :z_{crit}= \pm 1.96

Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

6 0
3 years ago
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