Nathan took his car in for service and repairs. He had a coupon for 10% off.

Mathematics

1 answer:

Olin [163]3 years ago

5 0

The answer would be $713.23

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PLZ HELP I WILL MARK AS BRAINLIEST

-Dominant- [34]

Answer:

7 square units

Step-by-step explanation:

As with many geometry problems, there are several ways you can work this.

Label the lower left and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.

The applicable formulas are ...

area of a trapezoid: A = (1/2)(b1 +b2)h

area of a triangle: A = (1/2)bh

So, our areas are ...

AQRS = AWSQE - AWSR - AEQR

= (1/2)(WS +EQ)WE -(1/2)(WS)(WR) -(1/2)(EQ)(ER)

Factoring out 1/2, we have ...

= (1/2)((2+5)·4 -2·2 -5·2)

= (1/2)(28 -4 -10) = 7 . . . . square units

4 0

3 years ago

Select the correct answer what is the range of the function shown in the graph?

Vedmedyk [2.9K]

Answer:

In the step by step

Step-by-step explanation:

Graph 1 : k(x)=(1/4)^x

Graph 2: f(x)=-(1/4)^x

Graph 3: g(x)=4^x

Graph 4: h(x)=-4^x

7 0

3 years ago

If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?

Keith_Richards [23]

$\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}$

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

$\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}$

so, the domain is all real numbers EXCEPT that one.

4 0

3 years ago

Let f={(1,2),(2,3),(5,6),(7,8) evaluate f(2)and f(5)?

Flauer [41]

Given:

$f=\{(1,2),(2,3),(5,6),(7,8)\}$