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3 years ago

Select all that apply.

Mathematics

1 answer:

wlad13 [49]3 years ago

7 0

The first and third option.

Hope this helps.

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Helpppp please anyone. I don't understand

vovikov84 [41]

The area is 21cm squared. u would have to find the length of the bottom triangle which is 14. than multiply that by the height which is 3. finally divide that all by 2 and youll get the area

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3 years ago

The bill at a restaurant came to $136.40 the patrons decide to leave a 15% tip what was the total tip including the bill

iogann1982 [59]

Answer: $156.86

Step by Step:

136.40 x .15 = 20.46

136.40 + 20.46 = 156.86

3 0

2 years ago

Find y when x=14 if y varies directly with x2 and y=72 when x=6

ICE Princess25 [194]

This should help you:

8 0

3 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago

PLEASE HELP! WILL GIVE 70 POINTS!!

Tresset [83]

Answer:

$A=189\ mm^2$

Step-by-step explanation:

<u>Surface Areas </u>

Is the sum of all the lateral areas of a given solid. We need to compute the total surface area of the given prism. It has 5 sides, two of them are equal (top and bottom areas) and the rest are rectangles.

Computing the top and bottom areas. They form a right triangle whose legs are 4.5 mm and 6 mm. The area of both triangles is

$\displaystyle A_t=2*\frac{b.h}{2}=b.h=(4.5)(6)=27 mm^2$