Let's solve this problem step-by-step.
STEP-BY-STEP SOLUTION:
In order to find the answer, we need to do as follows:
Average no. of people per km^2 = total no. of people ÷ total no. of people
Average no. of people per km^2 = 1, 080, 264, 388 ÷ 2, 973, 190
Average no. of people per km^2 = 363.335134317
Now we need to round the answer to the nearest whole number. In this case, we will be rounding down as displayed below:
Average no. of people per km^2 = 363 people
ANSWER:
Therefore, the answer is:
There are an average of 363 people per km^2 of land in India.
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I don't understand your question are you multiplying or what
Answer: 2.14 %
Step-by-step explanation:
Given : pH measurements of a chemical solutions have
Mean : 
Standard deviation : 
Let X be the pH reading of a randomly selected customer chemical solution.
We assume pH measurements of this solution have a nearly symmetric/bell-curve distribution (i.e. normal distribution).
The z-score for the normal distribution is given by :-

For x = 6.74

For x = 6.76

The p-value =

In percent, 
Hence, the percent of pH measurements reading below 6.74 OR above 6.76 = 2.14%