Equation of the parabola: y = ax^2 + bx + c. Find a, b, and c.
x of axis of symmetry:
x
=
−
b
2
a
=
3
-> b = -6a
Writing that the graph passing at point (1, 0) and point (4, -3):
(1) 0 = a + b + c -> c = - a - b = - a + 6a = 5a
(2) -3 = 16a + 4b + c --> -3 = 16a - 24a + 5a = -3a --> a = 1
b = -6a = -6; and c = 5a = 5
y
=
x
2
−
6
x
+
5
Check with x = 1: -> y = 1 - 6 + 5 = 0. OK
Answer:
a₁ = 38
Step-by-step explanation:
Given AP, where:
=============
<h3>Solution</h3>
aₙ = a₁ + (n-1)d
- a₈ = a₁ + 7d = a₁ + 7*(-2) = a₁ - 14
- a₁₂ = a₁ + 11d = a₁ + 11*(-2) = a₁ - 22
8a₈ = 12a₁₂
- 8(a₁ - 14) = 12(a₁ - 22)
- 2(a₁ - 14) = 3(a₁ - 22)
- 2a₁ - 28 = 3a₁ - 66
- 3a₁ - 2a₁ = -28 + 66
- a₁ = 38
Answer:
C) 6 ft
Step-by-step explanation:
Perimeter is just adding the side lengths together so...
31-15-10=x
6=x
so your answer is 6ft
