All categories

3 years ago

For lines c, d, and e.

Mathematics

1 answer:

USPshnik [31]3 years ago

5 0

Answer:

A) x = 6

B) ∠3 = 29°

C) ∠1 = 29°

D) ∠2 = 151°

Step-by-step explanation:

Given line e // line d and line c is transversal

Part A: If ∠3 = 5x-1 and ∠5 = 3x + 11 , find x

∠3 = ∠5 because alternate angles are congruent.

So, 5x - 1 = 3x + 11 Combine like terms

5x - 3x = 11 + 1

2x = 12

x = 6

Part B: If ∠3 = 5x-1 and ∠5 = 3x + 11 , find ∠3

∠3 = ∠5 because alternate angles are congruent.

So, 5x - 1 = 3x + 11 Combine like terms

5x - 3x = 11 + 1

2x = 12

x = 6

∴ ∠3 = 5x - 1 = 5 * 6 - 1 =30 - 1 = 29°

Part C: If ∠3 = 5x-1 and ∠5 = 3x + 11 , find ∠1

∠3 = ∠1 because vertically opposite angles are congruent

∠3 = 29°

∴∠1 = 29°

Part D: If ∠3 = 5x-1 and ∠5 = 3x + 11 , find ∠2

The angles 2 and 3 are supplementary angles.

∠3 = 29°

∠2 + ∠3 = 180°

∠2 = 180° - ∠3 = 180° - 29° = 151°

∴ ∠2 = 151°

You might be interested in

Help See the picture

den301095 [7]

42? I think I’m not sure

8 0

2 years ago

Find the value of n (2n + 4)º

MatroZZZ [7]

Answer:

I don't recognize this problem, please make sure the input is complete.

Step-by-step explanation:

it that the full problem?

5 0

3 years ago

Ariele is hiking down into the canyon. She starts at the rim and hikes down 55 feet in 234 minutes. If she continues at this rat

Aleksandr-060686 [28]

Answer:

This means that she will be 16.35 ft away from the rim in 15 minutes at this current rate.

Step-by-step explanation:

What we are asked here is imply to state how long in terms of distance would be Arielle position after 15 minutes

Now, 55 ft will take her 234 minutes

x ft will take her 15 minutes

x * 234 = 55 * 15

234x = 3825

x = 3825/234

x = 16.35 ft

This means that she will be 16.35 ft away from the rim in 15 minutes at this current rate.

7 0

3 years ago

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: ordinary differential equation ode integration separable variables initial value problem differential integral calculus

7 0

3 years ago

Aldo took a survey to show the number of people that liked different types of drinks.

Alecsey [184]

Umm I don’t really know if this is the answer but 26/the amount of the other flavors

8 0

2 years ago

Read 2 more answers