Answer:
∠2 ≅ ∠B
Step-by-step explanation:
Let the triangle be ABC,
Given that,
∠A = 50°
∠C = 65°
Using angle-sum property of the triangle,
∠A + ∠B + ∠C = 180°
50° + ∠B + 65° = 180°
∵ ∠B = 65° ...(i)
A.T.Q.
Two horizontal lines are extended making 3 angles. Two angles out of them are 50° and 65°.
Since the adjacent angles comprising a straight line is equals to 180°.
so,
∠2 + 50° + 65° = 180°
∠2 + 115° = 180°
∠2 = 180° - 115°
∵ ∠2 = 65° ...(ii)
Using (i) and (ii),
∠2 ≅ ∠B
Therefore, ∠2 and ∠B are congruent to one another.
Answer:
Not gonna lie I don't know and this is old but plz give me brainliest.
Step-by-step explanation:
For this case we have the following equation:
V = I * R
Where,
V: voltage
I: current
R: resistance
By clearing R we have:
R = V / I
Substituting the values:
R = (20) / (0.57)
R = 35.09 Ohms
Answer:
The resistance of the light bulb is:
R = 35.09 Ohms
Hello :
<span>a point on the y-axis is : P( 0, y)
</span>PA = PB or PA² = PB².... A(7, -7) B(1,1)
(7-0)²+(-7-y)² = (1-0)² + (1-y)²
49+49+14y+y² = 1+1-2y+y²
16y = - 96
y= - 6
