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katrin [286]
3 years ago
8

Please help on this really need help on this

Mathematics
2 answers:
stepan [7]3 years ago
6 0
Its reflected across the x axis then moved down 1 unit
ira [324]3 years ago
5 0

reflection across the x axis and rotation


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What does a sample space look like?
grin007 [14]

Answer:

A sample space is a collection or a set of possible outcomes of a random experiment. The sample space is represented using the symbol, “S”. The subset of possible outcomes of an experiment is called events. A sample space may contain a number of outcomes that depends on the experiment

Hope this helps even a little bit:)

6 0
2 years ago
Read 2 more answers
What is (2-7x)+34-6-(758+8)
pickupchik [31]

Step-by-step explanation:

2- 7x + 34 - 6-(766)

2-7x + 34 - 6 - 766

2 - 7x - 738

-7x - 736

-(7x + 736

5 0
3 years ago
What is the perimeter of a polygon with vertices at ​ (3, 2) ​, ​ ​ (3, 9) ​​, (7, 12) , ​ (11, 9) ​​, and ​​ ​ (11, 2) ​?
Furkat [3]
The perimeter of said polygon is 32.
5 0
3 years ago
Can someone help me with this
mash [69]

The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

Hence the (h,k) = (-2,-3)

<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

d =  \sqrt{(x1 - x2) {}^{2}  +  {(y1 - y2)}^{2} }  \\ r =  \sqrt{ {( - 2 - 0)}^{2} +  {( - 3 - ( - 3))}^{2}  }  \\ r =  \sqrt{ {( - 2)}^{2} +  {( - 3 + 3)}^{2}  }  \\ r =  \sqrt{ {4}^{2} + 0 }  \\ r =  \sqrt{4}  \\ r = 2

<h3>How to find the standard form of equation of the circle?</h3>

(h,k) = (-2,-3)

r = 2

subtitue the (h,k) and r values to get the standard form of equation of the circle.

(x - h) {}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

{(x - ( - 2))}^{2}  +  {(y - ( - 3))}^{2} =  {r}^{2}

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

Learn more about circle, refer:

brainly.com/question/24810873

#SPJ9

5 0
1 year ago
What is the range of f(x)? {x| -2
Lisa [10]

Answer:

I thing it should be x-4 because I don't get the question

5 0
2 years ago
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