Answer:
The prove is as given below
Step-by-step explanation:
Suppose there are only finitely many primes of the form 4k + 3, say {p1, . . . , pk}. Let P denote their product.
Suppose k is even. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
ThenP + 2 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 2 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠2. This is a contradiction.
Suppose k is odd. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
Then P + 4 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 4 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠4. This is a contradiction.
So this indicates that there are infinite prime numbers of the form 4k+3.
CL will always be the same as LD, the CD line is perpendicular to AB where the L is, so, the extreme points of CD will always be in the same distance of L.
Answer: 15.625
Step-by-step explanation:
F = 1000/(8^2) = 1000/64 = 15.625
X : the gas used by first car in 1 particular week
y : the gas used by second car in 1 particular week
The distance traveled by the second hand of the clock is 0.471 m.
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To calculate the distance the tip of the second hand of the clock travel in 45 seconds, we use the formula below.
<h3>Formula:</h3>
- L = 2πr∅/360.................. Equation 1
<h3> Where: </h3>
- L = distance traveled by the tip of the second hand.
- r = Length of the second hand
- ∅ = angle formed by the second hand of the clock
- π = pie
From the question,
<h3>Given:</h3>
- r = 10 cm = 0.1 m
- ∅ = (360×45/60) = 270°
- π = 3.14
Substitute these values into equation 1
- L = 0.1×2×270×3.14/360
- L = 0.471 cm.
Hence, The distance traveled by the second hand of the clock is 0.471 m
Learn more about distance traveled here: brainly.com/question/4931057
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