Answer:
D) x=![\frac{-2+-2\sqrt{7} }{3}](https://tex.z-dn.net/?f=%5Cfrac%7B-2%2B-2%5Csqrt%7B7%7D%20%7D%7B3%7D)
Step-by-step explanation:
The quadratic formula is : ![\frac{-b+-\sqrt{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%2B-%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D)
A in terms of this question=9
B in terms of the question is 12
C in terms of the question is -24.
This question is an example of a quadratic equation. To work this out you may first need a calculator. The first step is to substitute the values of a,b and c into the formula. So once substituted the formula of
becomes
. Although when written in a calculator there will not be a plus and minus button and so you would have to do this separately.
However when substituting the values it would be best practice to put them in brackets.
1) Substitute the values into the equation for +.
![\frac{(-12)+\sqrt{(12)^2-4*(9)*(-24)} }{2(9)}=\frac{-2+2\sqrt{7} }{3} /1.097167541](https://tex.z-dn.net/?f=%5Cfrac%7B%28-12%29%2B%5Csqrt%7B%2812%29%5E2-4%2A%289%29%2A%28-24%29%7D%20%7D%7B2%289%29%7D%3D%5Cfrac%7B-2%2B2%5Csqrt%7B7%7D%20%7D%7B3%7D%20%2F1.097167541)
2) Substitute the values into the equation for -.
![\frac{(-12)-\sqrt{(12)^2-4*(9)*(-24)} }{2(9)}=\frac{-2+2\sqrt{7} }{3} /-2.430500874](https://tex.z-dn.net/?f=%5Cfrac%7B%28-12%29-%5Csqrt%7B%2812%29%5E2-4%2A%289%29%2A%28-24%29%7D%20%7D%7B2%289%29%7D%3D%5Cfrac%7B-2%2B2%5Csqrt%7B7%7D%20%7D%7B3%7D%20%2F-2.430500874)
Missing question: Determine the distanced covered by Mary.
Solution:
Mary: 3 mph
Jerry: 4 mph
Jerry starts jogging after Mary had been walking for 15 minutes.
Distance Mary had walked before Jerry starts jogging = Speed * Time = 3*15/60 = 0.75 miles.
Time taken by Jerry to jog for 2 miles = Distance/Speed = 2/4 =1/2 = 0.5 hrs.
Since they stopped at the same time,
Distance Mary walked while Jerry jogged = Speed* Time = 3*0.5 = 1.5 miles
Therefore,
Total distance Mary walked = 0.75+1.5 = 2.25 miles.
y=3x+19
Step-by-step explanation:
equation parallel to y=3x+3 means having the same gradient .Here gradient is 3 where you equate equation with y=mx +c where m is the gradient and c is the y-intercept
Equation of line y=3x+c
you must find c ,replace point (-3,10) in equation y=3x+c
10=3(-3)+c
10=-9+c
10+9=c
c=19
equation of line parallel to y=3x+3 that passes through(-3,10) is y=3x+19
Answer:
- 627 miles north
- 747 miles east
Step-by-step explanation:
Bearing angles are measured east of north, so in (N, E) coordinates, the final position of the plane is ...
(1.5 h)(650 mi/h)(cos(50°), sin(50°)) = (975cos(50°), 975sin(50°)) mi
= (626.72, 746.89) mi
The plane will be 627 miles north and 747 miles east of its point of departure.
Answer:
Bsskdn ndndjdeiknn
Step-by-step explanation:
Djjddnnddndjxnndndnddbnxnxx c. XX cnddn