Answer:
The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 8 - 1 = 7
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.3246
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg
The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg
The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ:</u></h3>
<h3>
<u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>
<u>We </u><u>are </u><u>given </u><u>that </u><u>:</u>
- Height of cylinder = 21 cm
- Radius of cylinder = 24 cm
<u>Therefore, Volume :</u>
➙ V = πr²h
➙ V = ( 22 / 7 ) × ( 24 )² × ( 21 )
➙ V = ( 22 / 7 ) × 576 × 21
➙ V = ( 22 × 576 × 21 ) / 7
➙ V = 266112 / 7
➙ V = 38016
ㅤㅤ ㅤㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>volume</u><u> </u><u>of </u><u>given</u><u> </u><u>cylinder</u><u> </u><u>is </u><u>3</u><u>8</u><u>,</u><u>0</u><u>1</u><u>6</u><u> </u><u>cm³</u><u>.</u>
<h3>
<u>⳨ⲟⲅⲙⳙⳑⲇ ⳙ⳽ⲉ∂ :</u></h3>
The volume of cylinder is it's density which tells us the amount by which it can be filled by any material or the the amount of material which can be immersed in it.
The Formula for volume of cylinder is given by :
ㅤㅤㅤㅤㅤ➙ πr²h
From the graph we can see that in the interval [0,1] the value of y is less than 1.
In the interval [1,2] the value of y value is 2 to 4.
In the interval [2,infinity) the graph is going up, and the value of y is greater than or equal to 4.
Therefore, the graph going up after y=4 above the line.
Therefore, the minimum y-value is 4 after which the exponential function will always be greater than the linear function.
X= 1 2 3 that will be the possible solution
Answer:
x = pi/2 + 2 pi n x = pi + 2 pi n where n is an integer
x = 5pi /3 + 2 pi n
Step-by-step explanation:
8 cos^2 x + 4 cos x-4 = 0
Divide by 4
2 cos^2 x + cos x-1 = 0
Let u = cos x
2 u^2 +u -1 =0
Factor
(2u -1) ( u+1) = 0
Using the zero product property
2u-1 =0 u+1 =0
u = 1/2 u = -1
Substitute cosx for u
cos x = 1/2 cos x = -1
Take the inverse cos on each side
cos ^-1(cos x) = cos ^-1(1/2) cos ^-1( cos x) =cos ^-1( -1)
x = pi/2 + 2 pi n x = pi + 2 pi n where n is an integer
x = 5pi /3 + 2 pi n
