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3 years ago

Simplify (3v^3)^2/15v^7

Mathematics

2 answers:

leonid [27]3 years ago

8 0

<span>Combine like terms : (v2 - 5) x (3v + 7)</span>

liraira [26]3 years ago

5 0

13
3v
------------
5
(_Please give it the Brainiest answer_)

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2 years ago

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3 years ago

If f(x) = x2 and g(x) = 3x + 1, then g(f(2))= ?

andreyandreev [35.5K]

Answer:

The value of g[f(2)] = 13

Step-by-step explanation:

Given functions:

f(x) = x²

g(x) = 3x + 1

Find:

The value of g[f(2)]

Computation:

f(x) = x²

By putting x = 2 in f(x)

f(x) = x²

f(2) = 2²

f(2) = 2 × 2

f(2) = 4

So the value of f(2) = 4

Value of f(2) putting in g(x)

g(x) = 3x + 1

g[f(2)] = 3[f(2)] + 1

We know that f(2) = 4

So,

g[f(2)] = 3[f(2)] + 1

g[f(2)] = 3[4] + 1

g[f(2)] = 12 + 1

g[f(2)] = 13

The value of g[f(2)] = 13

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3 years ago

4. Han's younger sister is riding her tricycle in a straight line. After 3 s, her speed is 0.5 m/s. After 5 s, her speed is 1.5

liberstina [14]

Answer:

Han's younger sister accelerated at a rate of 0.5 meters per square second during that time.

Step-by-step explanation:

Let suppose that Han's younger sister accelerates at constant rate, then, acceleration ( $a$ ), measured in meters per square second, can be calculated by the following equation:

$a = \frac{v_{f}-v_{o}}{t_{f}-t_{o}}$

Where:

$t_{o}$ , $t_{f}$ - Initial and final times, measured in seconds.

$v_{o}$ , $v_{f}$ - Initial and final speeds, measured in meters per second.

If we know that $t_{o} = 3\,s$ , $t_{f} = 5\,s$ , $v_{o} = 0.5\,\frac{m}{s}$ and $v_{f} = 1.5\,\frac{m}{s}$ , the acceleration of the younger sister is: