Answer:
5x-4y = -32
Step-by-step explanation:
First write the equation in point slope form
y-y1 = m(x-x1)
y - -2 = 5/4 ( x- -8)
y+2 = 5/4 (x+8)
Multiply each side by 4 to clear the fraction
4( y+2 )= 4*5/4 (x+8)
4y +8 = 5(x+8)
4y+8 = 5x+40
Subtract 4y from each side
8 = 5x-4y +40
Subtract 40 from each side
-32 = 5x-4y
5x-4y = -32
Answer:
Hello
The answer is 3855'5
Step-by-step explanation:
At first change lbs to kg.
Then you'll change the kg to grkg×1000=gr
Given:
The function is 
.
To find:
The function 
.
Solution:
We have,
Substitute f(x)=y.
Interchange x and y.
Divide both sides by 3.
Taking power 4 on both sides.
Subtract 7 from both sides.
Substitute 
.
Therefore, the correct option is C.
The answer is 30 cubic inches.
If <span>5 chocolate candies are in 1 cubic inch, 150 </span><span>chocolate candies will be in x cubic inches:
</span>5 chocolate candies : 1 cubic inch = 150 chocolate candies : x<span> cubic inches
</span>5 : 1 = 150 : x
5 = 150 : x
x = 150 : 5
x = 30
So, if <span>150 chocolate candies are in a jar, the volume of the jar is 30 cubic inches.</span>
Assuming P (usually written in upper case) represents a force normal to a given cross section.
If a point load is applied to any point of the section, stress concentration will cause axial stress to vary.
The context of the question considers the uniformity of axial stress at a certain distance away from the point of application (thus stress concentration can be neglected).
If a force P is applied through the centroid, sections will be stressed uniformly. However, if the force P is applied at a distance "e" from the centroid, the equivalent load on the section equals an axial force and a moment Pe. The latter causes bending of the member, causing non-uniform stress.
If we assume A=(uniform) cross sectional area, and I=moment of inertia of the section, then stress varies with the distance y from the centroid equal to
stress=sigma=P/A + My/I
where P=axial force, M=moment = Pe.
Therefore when e>0, the stress varies across the section.
