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Olegator [25]
3 years ago
9

What is 50+15d=125 equivalent to

Mathematics
2 answers:
Serggg [28]3 years ago
8 0
The answer is d=5. Hope I helped you ❣️
zlopas [31]3 years ago
7 0

Step-by-step explanation:

50-50+15d =125-50

15d = 75

15d/15=75/15

d=5

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PLEASE HELP!!!
kaheart [24]

Answer:

angle B is 45 degree.

Step-by-step explanation:

since both radius are equal in a circle the triangle formed is ann isosceles triangle.

base angle of an isosceles triangle are equal

angle B be x

angle A = angle B (being base angles of a triangle)

then angle A is also x

angle A + angle B + angle C =180 degree (sum of interior angles of a triangle)

x + x + 90=180

2x =180-90

x=90/2

x=45 degree

6 0
3 years ago
Flashcard for geometry page 77
Nostrana [21]
What’s the question ???????
6 0
3 years ago
At Katya’s fruit stand, a basket of strawberries costs $4 and a basket of raspberries costs $9. In one morning, Katya sells 96 b
Tcecarenko [31]

Answer:

The number of strawberry baskets sold was 44

Step-by-step explanation:

Let

x ----> the number of strawberry baskets sold

y ---> the number of raspberries baskets sold

we know that

In one morning, Katya sells 96 baskets for $644

so

x+y=96 ----> equation A

4x+9y=644 ---> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (44.52)

see the attached figure

therefore

The number of strawberry baskets sold was 44 and the number of raspberries baskets sold was 52

4 0
3 years ago
What is y=5x+3 when the x variable is 1
ikadub [295]
The answer is 8 y=8 very easyyyy
3 0
3 years ago
Read 2 more answers
Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a
Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.064

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

6 0
3 years ago
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