Answer:
1. 3x-9+2y
2. 7x+6
Step-by-step explanation:
1. 2x + (x - 4) + (2y - 5)
2x+x-4+2y-5
3x-9+2y
2. 3(x - 2) + 4(x + 3)
3x+4x-6+12
7x+6
Here is how you solve this:
1- convert 2 1/2 to 4 3/4. 2 1/2 = 2 2/4 + 4 3/4= 6 5/4, 5/4 = 1 1/4= 6+1+ 1/4= 7 1/4.
2-15 1/3 - 7 1/4 = 8 1/12, 8 1/12 / 2= 4 1/4 and 3 5/6 is the answer.
On the 3rd and 4th day 4 1/4 in & 3 5/6in snow fell.
Answer:
37 is the smallest positive integer n such that n(n+1)(n+2) is divisible by 247.
Step-by-step explanation:
First we will find the prime factors of 247:
247 = 13 x 19 (which are both prime).
So now we need to find a number (the smallest one) that is of the form (n)(n+1)(n+2) (the product of three consecutive numbers) and that is divisible by both 13 and 19 (and therefore divisible by 247)
Let's take a look at the multiples of 13: 13, 26, 39, 52...
Let's take a look at the multiples of 19: 19, 38, 57...
We can see that the first time we have two multiples close together are the 38 (for 19) and the 39 (for 17).
So, if our number has both 38 and 39 as factors, then it will be divisible by 247.
However, we need not two but three consecutive numbers, and since we want the number to be the smallest positive integer, we will add 37 (since our other choice would be to add 40 and that would make the number bigger) and thus our number is (37)(38)(39) or in other words (37)(37 + 1)(37 + 2) and therefore this is the smallest positive number such that n(n+1)(n+2) is divisible by 247.
To find out the simplest form of 44 over 66, we simply can identify the LCD, which in this case, is 3. So now that we know the denominator of our simplified fraction, most people will be able to estimate that 44 is 2/3 of 66.
Your answer is :
9514 1404 393
Answer:
B, C, E
Step-by-step explanation:
When the central angles are congruent, the corresponding triangles are congruent:
ΔJHK ≅ ΔLHM . . . . selection E
and the base chords are congruent:
ML ≅ JK . . . . selection B
The subtended arcs are also congruent, so adding arc LK to each will result in congruent arc measures:
arc MLK ≅ arc LKJ . . . . selection C
