5(8x - 10) - 10x + 25(8x - 10) - 10x + 2
= (40x - 50) - 10x + (200x - 250) - 10x + 2
= 40x - 50 - 10x + 200x - 250 - 10x + 2
= (grouping like terms together)
= 40x - 10x + 200x - 10x - 50 - 250 + 2
= 220x - 298
2x^3y + x^2y^2 + 4xy^3
GCF = xy
V = Displacement / Time
V = 5 m / 15 s
V = 1/3 m/s or 0.33 m/s
If the sales department wants to place an order for 253,625 third grade math books for a region. How can the sale manager estimate the number of math books to be sure that there are more then enough is: The manager should carryout survey based on the number of people per class and provide 25,362 books.
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How the sale can manager estimate the number of math books </h3>
Since extra math's books will be needed after giving out the available math's books.
Hence:
Additional maths books=10%× 253,625
Additional maths books=25,362 books
Based on the above calculation the manager should carryout survey based on the number of people per class and provide them with 25,362 books.
Therefore how can the sale manager estimate the number of math books to be sure that there are more then enough is that the manager should carryout survey based on the number of people per class and provide 25,362 books.
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