Answer:
36s^3
Step-by-step explanation:
The first 9 is in the ten thousands place. the second 9 is in the thousands place.
90,000 < 9,000
p must be positive. If p is negative, the equation has no real solutions. This is because any number to the power of 2 is always positive. Therefore, if p is positive, there are 2 real number solutions: sqrt(p) and -sqrt(p).
Hope this helps,
Bri