Answer:
53.57%
Step-by-step explanation:
We have to calculate first the specific number of events that interest us, if at least 3 are girls, they mean that 2 are boys, therefore we must find the combinations of 3 girls of 5 and 2 boys of 3, and multiply that, so :
# of ways to succeed = 5C3 * 3C2 = 5! / (3! * (5-3)!) * 3! / (2! * (3-2)!)
= 10 * 3 = 30
That is, there are 30 favorable cases, now we must calculate the total number of options, which would be the combination of 5 people from the group of 8.
# of random groups of 5 = 8C5 = 8! / (5! * (8-5)!) = 56
That is to say, in total there are 56 ways, the probability would be the quotient of these two numbers like this:
P (3 girls and 2 boys) = 30/56 = 0.5357
Which means that the probability is 53.57%
Answer:
1/4
Step-by-step explanation:
5/20 = 1/4
hope this helps
Sum of three consecutive odd integers = 
The values of the three integers.
Let us assume the three consecutive odd integers to be 
, 
and 
.
As per the condition, we have
Now, collect the like terms.
Therefore, the three consecutive odd integers whose sum is are 
, 
and 
respectively.
⇢ L. H. S. = R. H. S.
Answer:
(2, 3)
Step-by-step explanation:
2x + 5y = 19
5y = -2x + 19
y = 
P(abscissa, ordinate)
P(x, 1.5x)
P(2, 3)
3 = 15/5
3 = 3
Answer:
9th term of the sequence.
Step-by-step explanation:
well, all they are doing in this problem is adding the numbers. 3+3=6+6=12+12=24+24=48 and so on. If you keep going, you'll get 48+48=96+96=192+192=384+384=768+768=1536
