Well, this depends on the number of topping ingredients you have for each serving of nachos. The general solution will be simply to add all the topping ingredients for each type. Assuming there is an average of 7 topping ingredients for every type, namely: cheese<span>, fried beans, sour cream, onions, jalapeños, salsa, and guacamole. Hence,
Topping Ingredients = 7*256 = 1,792</span>
X=-1.8
To solve first use the distributive property to change the equation to -2x+1 1/3+1=5
Then you subtract 1 from 5 so then the equation looks like this: -2x+1 1/3=4
Next subtract 1 1/3 from 4 to get 3.6
then divide it by -2 and you get -1.8
Given :
Two equation
and
.
To Find :
The point of intersection of these lines .
Solution :
We will use elimination method :
From equation 1 :
![x_1=7-5x_2](https://tex.z-dn.net/?f=x_1%3D7-5x_2)
Putting value of
in equation 2 we get :
![(7-5x_2)-2x_2=-2\\\\7-7x_2=-2\\\\x_2=\dfrac{9}{7}](https://tex.z-dn.net/?f=%287-5x_2%29-2x_2%3D-2%5C%5C%5C%5C7-7x_2%3D-2%5C%5C%5C%5Cx_2%3D%5Cdfrac%7B9%7D%7B7%7D)
Putting value of
in equation 1 we get :
![x_1+5\times \dfrac{9}{7}=7\\\\x_1=\dfrac{4}{7}](https://tex.z-dn.net/?f=x_1%2B5%5Ctimes%20%5Cdfrac%7B9%7D%7B7%7D%3D7%5C%5C%5C%5Cx_1%3D%5Cdfrac%7B4%7D%7B7%7D)
Therefore , point of interaction is
.
Hence , this is the required solution .
<h3>Answers: </h3><h3>Use <u>60 gallons</u> of the 30% solution</h3><h3>Mix with <u>40 gallons</u> of the 80% solution</h3>
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Work Shown:
x = amount of the 30% solution (in gallons)
y = amount of the 80% solution (in gallons)
The two amounts must add to 100 as this is the total we want, so x+y = 100 which becomes y = 100-x after subtracting x from both sides
The expression 0.30*x represents the amount of pure alcohol from the first batch, while 0.80*y represents the amount of pure alcohol from the second batch. In total, we have 0.30*x+0.80*y gallons of pure alcohol. We want 50 gallons of pure alcohol (50% of 100 gallons is 50 gallons), therefore we end up with this equation: 0.30*x+0.80*y = 50
Let's use substitution to isolate the variables.
0.30*x+0.80*y = 50
0.30*x+0.80*(100-x) = 50 ... replace y with 100-x
0.30*x+0.80*(100)+0.80*(-x) = 50 ... distribute
0.30*x+80-0.80x = 50
-0.50*x+80 = 50
-0.50*x+80-80 = 50-80 ... subtract 80 from both sides
-0.50*x = -30
x = -30/(-0.50) .... divide both sides by -0.50
x = 60
If x = 60, then y is...
y = 100-x
y = 100-60
y = 40
Answer:
36.04
Step-by-step explanation:
you just divide your welcome