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N76 [4]
3 years ago
15

HELP ASAP

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0

Answer:

∠RQT ≅ ∠PQS  (by the vertical angles theorem)

Step-by-step explanation:

Given: RT || SP, RQ ≅ QP, RP bisects ST at Q

To prove: ΔRQT ≅ ΔPQS

Proof:

It is given that RT || SP, RQ ≅ QP, RP bisects ST at Q, thus TQ=QS

From ΔRQT and  ΔPQS, we have

RQ ≅ QP (Given)

∠RQT ≅ ∠PQS (by the vertical angles theorem)

TQ ≅ QS (by the definition of segment bisector)

Therefore, by SAS rule of congruency, we have

ΔRQT ≅ ΔPQS

Hence proved.

mixas84 [53]3 years ago
5 0

SAS theorem states that if <u>two sides</u> and the <u>included angle</u> of one <u>triangle</u> are <u>congruent</u> to <u>two sides</u> and the <u>included angle</u> of another <u>triangle</u>, then these two <u>triangles are congruent</u>.

1. RQ ≅ QP (given)

2. If RP bisects ST at Q, then  TQ ≅ QS (by the definition of segment bisector).

3. ∠RQT,  ∠PQS are vertical angles (angles that are vertically opposite to each other when lines PR and ST intersect, Q is the common vertex).

∠RQT ≅ ∠PQS  (by the vertical angles theorem).

Vertical angles theorem  states that vertical angles are always congruent.

According to SAS theorem, ΔRQT ≅ ΔPQS.

Answer: vertical angles theorem

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