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3 years ago

You want to see if playing music makes plants grow taller. What is the dependent variable in this experiment?

Mathematics

1 answer:

Sladkaya [172]3 years ago

5 0

Answer: the hight of the plant is the dependent variable bc the independent variable is music being played

hoped this helped (let me know if it did) :)

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Can someone please help me its urgent!!!!!!!!!!<br> 3x + 11 = 3x - 11

user100 [1]

Answer:

$\Large\boxed{\mathsf{\Rightarrow NO\quad SOLUTIONS}}$

Step-by-step explanation:

<h3><u>TO SOLVE:</u></h3>

Isolate by the x on one side of the equation.

<h3><u>SOLUTIONS:</u></h3>

First, subtract 3x from both sides.

$\displaystyle \Rightarrow \mathsf{3x+11-3x=3x-11-3x}}$

Solve.

$\displaystyle \mathsf{11=-11}$

Sides are NOT equal.

$\Large\boxed{\mathsf{\Rightarrow THERE \quad ARE \quad NO \quad SOLUTIONS}}}$

Therefore, there are no solutions.

6 0

3 years ago

Select the correct answer.

adoni [48]

The correct answer is b) 2

8 0

3 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago

VARVARA [1.3K]

I think the 2nd one I'm not really sure

8 0

3 years ago

Triangle CAT was rotated to create triangle C’A’T’. Describe the transformation using details and degrees

Elis [28]

Answer:

As this triangle is being transformed by rotation, the angles will stay same as well as the sides and other details, if you are doing this on a coordinate plane, then the points of the triangle would be changed and nothing else

If my answer helped, please mark me as the brainliest!!

Thank You!

5 0

3 years ago