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3 years ago

Determine the value of cot 36 degrees

Mathematics

2 answers:

zavuch27 [327]3 years ago

8 0

Cot( \theta) = 1/tan( 1\theta)
Tan (36o) = 0.7265
1 / tan(36o) = 1.3765

D <<<< answer

blsea [12.9K]3 years ago

7 0

Answer:

option D

Step-by-step explanation:

cot(36°)

Cot can be written as $\frac{1}{tan}$

So cot(36)= $\frac{1}{tan(36)}$

Tan is positive in first and third quadrant

$\frac{1}{tan(36)}$ gives us positive value because 36 degree is in first quadrant.

Use calculator to find the value of $\frac{1}{tan(36)}$

$\frac{1}{tan(36)}$ = 1.37638192

option D

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Answer:

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Step-by-step explanation:

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3 years ago

Find a quadratic polynomial with integer coefficients which has x = 2/9, ± SQRT23/9 as its real zeros.

melomori [17]

Answer:

The quadratic polynomial with integer coefficients is $y = 81\cdot x^{2}-36\cdot x -19$ .

Step-by-step explanation:

Statement is incorrectly written. Correct form is described below:

<em>Find a quadratic polynomial with integer coefficients which has the following real zeros: </em> $x = \frac{2}{9}\pm \frac{\sqrt{23}}{9}$ <em>. </em>

Let be $r_{1} = \frac{2}{9}+\frac{\sqrt{23}}{9}$ and $r_{2} = \frac{2}{9}-\frac{\sqrt{23}}{9}$ roots of the quadratic function. By Algebra we know that:

$y = (x-r_{1})\cdot (x-r_{2}) = x^{2}-(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2}$ (1)

Then, the quadratic polynomial is:

$y = x^{2}-\frac{4}{9}\cdot x -\frac{19}{81}$

$y = 81\cdot x^{2}-36\cdot x -19$

The quadratic polynomial with integer coefficients is $y = 81\cdot x^{2}-36\cdot x -19$ .

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2 years ago

What is the standard form of the linear function that passes

babunello [35]

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• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

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