Answer:
787/32 or 24.59375
Step-by-step explanation:
I just looked it up lol
Tanα=y/x
α=arctan(y/x), we are given the point (3.2, 6.2) so:
α=arctan(6.2/3.2)°
α=arctan(1.9375)°
α≈62.7° (to nearest tenth of a degree)
Answer:
h = 13.333 +693.333/r
Step-by-step explanation:
For h hours, Brandee's pay will be ...
pay = 40r +(h -40)(1.5r) . . . . 40 hours at rate r + overtime (h-40) hours at 1.5r
pay = 40r +1.5hr -60r . . . . . eliminate parentheses
pay = 1.5hr -20r . . . . . . . . . . collect terms
Solving for h, we have ...
pay +20r = 1.5hr . . . . . . . . . . add 20r
h = (pay +20r)/(1.5r) . . . . . . . . divide by 1.5r
For the given pay of 800 +240 = 1040, we have ...
h = (1040 +20r)/(1.5r)
h = 13.333 +693.333/r . . . . . simplify to 2 terms
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<em>Additional comments</em>
You need to know r to find the number of hours Brandee worked. She got paid $800 for a presumed 40-hours of regular time, so made r = $20 per hour. The above formula will tell you she worked 48 hours in the pay period.
Answer:
Step-by-step explanation:
When using the substitution method we use the fact that if two expressions y and x are of equal value x=y, then x may replace y or vice versa in another expression without changing the value of the expression.
Solve the systems of equations using the substitution method
{y=2x+4
{y=3x+2
We substitute the y in the top equation with the expression for the second equation:
2x+4 = 3x+2
4−2 = 3x−2
2=== = x
To determine the y-value, we may proceed by inserting our x-value in any of the equations. We select the first equation:
y= 2x + 4
We plug in x=2 and get
y= 2⋅2+4 = 8
The elimination method requires us to add or subtract the equations in order to eliminate either x or y, often one may not proceed with the addition directly without first multiplying either the first or second equation by some value.
Example:
2x−2y = 8
x+y = 1
We now wish to add the two equations but it will not result in either x or y being eliminated. Therefore we must multiply the second equation by 2 on both sides and get:
2x−2y = 8
2x+2y = 2
Now we attempt to add our system of equations. We commence with the x-terms on the left, and the y-terms thereafter and finally with the numbers on the right side:
(2x+2x) + (−2y+2y) = 8+2
The y-terms have now been eliminated and we now have an equation with only one variable:
4x = 10
x= 10/4 =2.5
Thereafter, in order to determine the y-value we insert x=2.5 in one of the equations. We select the first:
2⋅2.5−2y = 8
5−8 = 2y
−3 =2y
−3/2 =y
y =-1.5
