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tatuchka [14]
3 years ago
5

Which of the following best explains why the diversity of organisms decreases as you move from shallow seas to deep oceans? (2 p

oints) The levels of oxygen in the deep ocean are too high for many organisms to thrive. The low temperatures of the deep ocean would freeze most organisms. The salinity of the deep ocean is too high for most organisms to live. The lack of sunlight in the deep ocean limits the types of organisms that can survive.
Biology
2 answers:
Anna [14]3 years ago
7 0

Answer:

The lack of sunlight in the deep ocean limits the types of organisms that can survive.

Explanation:

Limiting factors are biotic or abiotic environmental factors that limit the distribution of organisms in that an environment. The factor varies from environment to environment, habitat to habitat and biome to biome.

Oxygen level, temperature, salinity and light are indeed some of the abiotic factors limiting the distribution of organisms in the seas/oceans.

However, oxygen levels in deep ocean cannot be too high for organisms to survive, and while variation in temperature do exist between shallow and deep ocean, it is never to the point of freezing. Also, while salinity do limit the distribution of organisms in the ocean, no part of the ocean is too salty for marine organism.

<em>The major limiting factor is light. While the shallow end of the ocean is adequately illuminated to sustain photosynthetic and other diverse forms of organisms, the deep end is occupied by less diverse organisms that have developed necessary adaptation to low light. </em>

shepuryov [24]3 years ago
3 0
The lack of sunlight in the deep ocean limits  the types of organisms that can survive

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1. Would the pollution problems caused by cars and trucks be completely solved if they all became electrically powered overnight
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6 0
2 years ago
In a plant, leaf color and leaf shape are controlled by two linked genes Leaves of the wild-type plant are red. A recessive muta
Brrunno [24]

Solution :

Red is dominant over the white leaves and pointed is dominant over smooth.

Red = R ,    white = r

Pointed = P ,   smooth = p

Red, pointed x white,smooth ------ Parents

RRPP                 rrpp

RP                      rp  ----------------- Gametes

         RrPp    -------- $F_1$

  (red, pointed)

When this $F_1$ is test crossed,

RrPp  x  rrpp     ----  $F_1$ test cross

Gametes   → rp

RP ---------- RrPp - red, pointed - 36 parental type

Rp ---------- Rprp - red, smooth - 14 re- combination

rP ----------- rrPp - white pointed - 10 re- combination

rp ----------- rrpp - white, smooth - 40 - parental type

                                    Total =   100

As this ratio is deviating from 1:1:1:1, it indicated the two genes are linked.

Linkage strength = percentage of crossing over = map distance between the genes.

Percentage crossing = recombination frequency = percentage of recombination.

Recombination frequency $=\frac{\text{total no. of recombination}}{\text{total no. of progeny}}\times 100$

                                         $=\frac{14+10}{100} \times 100$

                                         = 24 %

                                        = 24 map units

4 0
3 years ago
Please answer ASAP!!
Serhud [2]
That looks right to me


4 0
3 years ago
Read 2 more answers
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