The answer you are looking for is B. 15
We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft
The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
Answer:
Step-by-step explanation:
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9514 1404 393
Answer:
v = 39; w = 47; x = 94; y = 39; z = 47
Step-by-step explanation:
The figure shows v° and 51° are complementary, as are z° and 43°.
v° = 90° -51° = 39°
z° = 90° -43° = 47°
Vertical angles are congruent.
y° = v° = 39°
w° = z° = 47°
And the angle x° is a vertical angle with the sum of 51° and 43°.
x° = 43° +51° = 94°
