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Romashka [77]
4 years ago
9

Locate the vertical asymptotes, and sketch the graph of y = sec (x - π) + 3.

Mathematics
1 answer:
8_murik_8 [283]4 years ago
6 0
Since secant is the inverse of cosine function, when the cosine function has a 'zero' the secant will have a vertical asymptote.

Graphing a cosine with a right shift of pi, the zeros would be at pi and 2pi.
This will make the vertical asymptotes of the secant function be at pi and 2pi.

I hope you understand.

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Help! need these answers filled in for school asap
vampirchik [111]

Answer:

Given : JKLM is a rectangle.

Prove: JL ≅ MK

Since, by the definition of rectangle all angles of rectangles are right angle.

Thus, In rectangle JKLM,

∠ JML and  ∠KLM are right angles.

⇒ ∠ JML ≅ ∠KLM

Since, JM ≅ KL   (Opposite sides of rectangles are congruent)

ML ≅ ML  ( Reflexive )

Thus, By SAS congruence postulate,

Δ JML ≅ Δ KLM

⇒ JL ≅ MK  ( because corresponding parts of congruent triangles are congruent)

Hence proved.

3 0
3 years ago
Find the distance between c (4,7) and d (4,12)
Tanzania [10]
Easy
see, the x terms didn't move (x,y)

so
from 7 to 12
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8 0
3 years ago
What is x + 15 > 3?
Over [174]

Answer:

hmm

Step-by-step explanation:

5 0
3 years ago
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If angle ABC is congruent to angle CBD, find x.
OLEGan [10]
4x + 30 = 5x + 20
30 - 20 = 5x - 4x
10 = x <==
3 0
3 years ago
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Challenge A gold mine has two elevators, one for equipment and another for the miners. The
OLEGan [10]

Step-by-step explanation:

The equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface

ii. The miners elevator is deeper than that of the equipment.

The speed of an object is the rate at which the object moves.

i.e speed = \frac{distance}{time}

time

distance

Thus,

Speed of the equipment elevator = 4 feet per second

Speed of the miners elevator = 15 feet per second.

Time of descent of the equipment elevator = 30 + 14

= 44 seconds

So that, the distance of the elevator at this time is;

speed = \frac{distance}{time}

time

distance

⇒ distance = speed x time

= 4 x 44

= 176

distance = - 176 feet

The distance of the miners elevator after 14 seconds is:

speed = \frac{distance}{time}

time

distance

⇒ distance = speed x time

= 15 x 14

= 210

distance = - 210 feet

Thus after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface.

Therefore, the miners elevator is deeper than that of the equipment.

6 0
3 years ago
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