Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
Step-by-step explanation:
(-9-7)/(0-1)= -16/-1= 16
y - 7 = 16(x - 1)
y - 7 = 16x - 16
y = 16x - 9
Answer:
187. 5
Step-by-step explanation:
If 2h=75km
Then 5h=?(if more, Less divide)
5÷2×75km =187.5km
Answer:
The midpoint is ( 7,5)
Step-by-step explanation:
To find the x coordinate of the midpoint, add the x coordinate of the endpoints and divide by 2
( 4+10)/2 = 14/2 = 7
To find the y coordinate of the midpoint, add the y coordinate of the endpoints and divide by 2
(8+2)/2 = 10/2 = 5
The midpoint is ( 7,5)
Answer:
The equation that represents the new path is y=(1/2)x-2
Step-by-step explanation:
step 1
Find the slope of the give line
we have
y=-2x-7
so
the slope m is equal to
m=-2
step 2
Find the slope of the perpendicular line to the given line
Remember that
If two lines are perpendicular, then their slopes are opposite reciprocal of each other
so
we have
m=-2 -----> slope of the given line
therefore
The slope of the perpendicular line is equal to
m=1/2
step 3
With m=1/2 and the point (-2,-3) find the equation of the line
y-y1=m(x-x1)
substitute
y+3=(1/2)(x+2)
y=(1/2)x+1-3
y=(1/2)x-2 -----> equation that represent the new path
