Least common multiple of 60 is code for "it's a really small number."
Less than or equal to 12 confirms that theory.
GCF of the two numbers is 2 tells me "it's the smallest numbers around."
The answer is 2 and 4. Their multiples can arrive at 60, they are less than 12, and the GCF for both numbers is 2.
Hi student, let me help you out! :)
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
We are asked to calculate the circumference of the two circles; all the required information is given to us.
![\triangle~\fbox{\bf{KEY:}}](https://tex.z-dn.net/?f=%5Ctriangle~%5Cfbox%7B%5Cbf%7BKEY%3A%7D%7D)
- The formula for the circumference is:
.
'
In this formula,
![\star~\mathrm{C=Circumference; \\ \pi =pi,\;which\;is\;3.14; d=diameter}}](https://tex.z-dn.net/?f=%5Cstar~%5Cmathrm%7BC%3DCircumference%3B%20%5C%5C%20%5Cpi%20%3Dpi%2C%5C%3Bwhich%5C%3Bis%5C%3B3.14%3B%20d%3Ddiameter%7D%7D)
------------------------------------------
Question #1
------------------------------------------
<u>Circumference of Circle</u>
<u></u>
<h3>Given value(s):</h3>
So to solve for circumference, we should substitute 10 for y, which gives us:
![\mathrm{C=10\pi}](https://tex.z-dn.net/?f=%5Cmathrm%7BC%3D10%5Cpi%7D)
Circumference:
![\bigstar~\mathrm{\underline{C=31.4\:cm}}](https://tex.z-dn.net/?f=%5Cbigstar~%5Cmathrm%7B%5Cunderline%7BC%3D31.4%5C%3Acm%7D%7D)
------------------------------------
Question #2
-------------------------------------
This time, the diameter is 6 units. We follow the same steps to find the circumference:
![\mathrm{C=6\pi }](https://tex.z-dn.net/?f=%5Cmathrm%7BC%3D6%5Cpi%20%7D)
Upon multiplication,
![\bigstar~\mathrm{\underline{C=18.8\:cm}}](https://tex.z-dn.net/?f=%5Cbigstar~%5Cmathrm%7B%5Cunderline%7BC%3D18.8%5C%3Acm%7D%7D)
Hope it helps you out! :)
Ask in comments if any queries arise.
#StudyWithBrainly
~Just a smiley person helping fellow students :)
Answers:
A''(3, 0); B''(3, 2); C''(1, 1); D''(1, -1)
Explanation:
We perform the reflection across y=x first. This reflection switches the x- and y-coordinates; this maps:
A(2, 4)→A'(4, 2)
B(4, 4)→B'(4, 4)
C(3, 2)→C'(2, 3)
D(1, 2)→D'(2, 1)
Next we perform the translation. This translation shifts the figure 1 unit left and 2 units down, by subtracting 1 from the x-coordinate and 2 from the y-coordinate. This maps:
A'(4, 2)→A''(3, 0)
B'(4, 4)→B''(3, 2)
C'(2, 3)→C''(1, 1)
D'(2, 1)→D''(1, -1)