the
complete question in the attached figure
<span>1. In the diagram below , lines a and b are parallel and cut by traversal, t of angle 3 is 120 degrees, find the measure of angle 7.
</span>∡3=∡7------------- > <span>corresponding angles
the answer is </span>
∡7=120 degrees
<span>2. in the diagram below , lines a and b are parallel and cut by traversal, t of angle 2 is 50 degrees, find the measure of angle 8.
</span>∡2=∡8------------- > <span>alternate exterior angles
</span>
the answer is ∡8=50 degrees
<span>3. In the diagram below , lines a and b are parallel and cut by traversal, t of angle 6 is 50 degrees, find the measure of angle 4.
</span>∡6=∡4------------- > <span>alternate interior angles
</span>
the answer is ∡4=50 degrees
It will take 2 and 1/2 hours to plant the 35 flowers.
Answer:
the answer 402
Step-by-step explanation:
Answer:
<u>Area = 34.2 cm²</u>
Step-by-step explanation:
The general formula of the area of the triangle is half the product of two sides multiplied by the sine the angle between them.
So, for the given triangle ABC
AC = 9 cm, AB = 8 cm, CB = 10 cm
Area = 0.5 AC * AB * sin A or 0.5 BC * BA * sin B or = 0.5 CA * CB * sin C
Using the first form, so we need the measure of angle A
Using cosine low: cos A = (b² + c² - a²)/(2bc)
Where: a = BC = 10 , b = AC = 9 and c = AB = 8
So. cos A = (9² + 8² - 10²)/(2 * 9 * 8 ) = 0.3125
∠A = cos⁻¹0.3125 = 71.79°
So, Area = 0.5 AC * AB * sin A = 0.5 * 9 * 8 * sin 71.79° = 34.2 cm²
<u>So, Area = 34.2 cm²</u> to the nearest one decimal place