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3 years ago

Will the opposite of zero always sometimes never be be zero explain your reasoning

1 answer:

4 0

always because the opposite of a positive is a negative, and the opposite of a positive is a negative. But zero is neither positive or negative, therefore is has no real opposite and is zero.

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Right the slope intercept form for the line that travels through (4,-1) and is parallel to y=1/4x

ololo11 [35]

Answer:

Step-by-step explanation:

The slope is given to you by the line y = 1/4 x

The slope is just read as the number in front of x providing that the coefficient of y is 1. If that is not so, then you must divide by the coefficient in front of y. So far what you have is y = 1/4 x + b.

The second part of the question is to use the given point to find b.

x = 4

y = -1

b = ? substitute x and y to find b

y = 1/4 * 4 + b

- 1 = 1/4 * 4 + b

-1 = 1 + b

-2 = b

The equation of the line is y = 1/4 x - 2 Just to confirm this, I'm going to include the graph with the point 4,-1 on it.

4 0

2 years ago

8. The two triangles are congruent as suggested by their appearance. Find the value of all the variables. The

adelina 88 [10]

Answer: d is 53 degrees, c is 5, g is 13, e is 90 degrees, f is 37 degrees, b is 12 .

Step-by-step explanation:

Since they're congruent you just compare the two and replace them. You have the answers on both sides, they're just split up. So look at one side, then the other, and see what you can find. Repeat.

8 0

2 years ago

Read 2 more answers

Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

$\implies k=\dfrac{19}{6}$

<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

$\implies -3=6.5k$

$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

$\implies 3=9.5k$

$\implies k=\dfrac{6}{19}$

6 0

1 year ago

How much less would a 23-year-old female pay for a $25,000 policy of 20 year life insurance (@ $2.90 per $1000) than straight li

mojhsa [17]

<u>Answer</u>:

The female would pay $322.00 less for a policy of $25,000

<u>Step-by-step explanation:</u>

Since we have given that

Amount for policy = $25000

If she opt for 20 year life insurance at $2.90 per $1000.

so, her amount of premium becomes

$25000\times \frac{2.9}{1000}$

=$72.50

If she opt for straight life insurance at $15.78 per $1000,

Then, her amount of premium becomes

$25000 \times \frac{15.78}{1000}$

= $394.50

Difference between them is given by

$394.50-$72.5 = $322.00

5 0

3 years ago

Read 2 more answers

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

6 0

2 years ago