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ladessa [460]
3 years ago
11

A student must choose to participate in two different events during field day. There are four track events, two academic events,

and six team sports events. What is the approximate probability that the student will choose to participate in two team sports?
0.114
0.227
0.273
0.545
Mathematics
2 answers:
borishaifa [10]3 years ago
5 0

Answer:

0.227

Step-by-step explanation:

Arlecino [84]3 years ago
4 0

Answer:

.227

Step-by-step explanation:

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B. 3x+5−4x=−(x+8)

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A bottle of tnt tonic contains 10 1/2 ounces and sells for 98¢ what is the cost per ounce
Rashid [163]

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4 0
4 years ago
Give the equation of the line that is perpendicular to y= (1/2)x -1 and passes through the point (3,4)
nexus9112 [7]

Answer: y = -2x + 10

Step-by-step explanation:

Two lines are said to be perpendicular if the product of their slope = -1, that is , if m_{1} is the slope of the first line and m_{2} is the slope of the second line , if the two lines are perpendicular , then m_{1}m_{2} = -1

The equation of the line given :

y = 1/2x - 1

comparing with the equation of line in slope intercept form

y = mx + c , where m is the slope and c is the y - intercept , it implies that

m_{1} = 1/2

Therefore :

m_{2} = -2

To find the equation of the line with slope -2  and passes through the point ( 3 , 4 ) we will use the formula

y-y_{1} = m (x-x_{1} )

y - 4 = -2 ( x - 3 )

y - 4 = -2x + 6

y = -2x + 6 + 4

y = -2x + 10

7 0
4 years ago
Find the probability that the mean annual preciptiation will be between 32 and 34 inches. variable is normally distributed
liq [111]
Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.

This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.  
                                                                     34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
                                                                           1.9
                                                                      32 in - 31.2 in
and that to the left of 32 in   is               z = ---------------------- = 0.421
                                                                             1.9

Know how to use a table of z-scores to find these two areas?  If not, let me know and I'll go over that with you.


My TI-83 calculator provided the following result:

normalcdf(32, 34, 31.2, 1.9) = 0.267  (answer to this sample problem)

5 0
3 years ago
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