First you would start getting the denominators to the same number and you could do this by multiplying 9/10 by 4, and 7/8 by 5 to get the denominators to 40 and when you add the fractions you get 71/40 so the answer would be D. About 2
Answer:
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formula : l x B = 10 x 16 = 160 sq
Step-by-step explanation:
MID POINT =[(X1 +X2)/2 , (Y1 +Y2)/2]
WE KNKW THAT A(2,–8) AND THE MID POINT IS (3,3)
SUBSTITUTING INTO THE EQUATION ABOVE
(3,3) = [(2+ X2)/2 ,(–8+ Y2)/2]
EQUATING THE X COORDINATES
=> 3 = (2+ X2)/2 (CROSS MULTIPLY)
=> 6 = 2 + X2
X(subscript 2)= 4
EQUATING THE Y COORDINATES
=> 3 =(–8 +Y2)/2 (CROSS MULTIPLY)
6 = –8 +Y2
=> Y(subscript 2)= 14
THEREFORE THE COORDINATES OF B ARE (4 ,14)
hope this helps :)
Answer:
C. cot theta
Step-by-step explanation:
(csc theta -cot theta )/(sec theta -1)
csc = 1/ sin
cot = cos / sin
sec = 1 / cos
Let x = theta
(1/ sin x -cos x / sin x )/(1/ cos x -1)
Getting a common denominator in the denominator and combining terms
(1- cos x)/ sinx / ( 1 - cos x) / cos x
(1- cosx) (1- cosx)
----------- ÷ ------------
sinx cos x
Copy dot flip
(1- cosx) cosx
----------- * ------------
sinx 1 -cos x
Cancel like terms
cos x / sin x
cos / sin = cot
cot x
cot theta
Answer:
{x∈R | 
, x∉Z}
Step-by-step explanation:
Given the function y=3tan(2/3x)
We know that tangent is a function that's continuous within it's domain but not continuous on all real numbers
Also, the roots of y=3tan(2/3x) is 
where n is an integer
Note that the domain of the function cannot be within
Therefore, {x∈R | , x∉Z}
