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maw [93]
3 years ago
10

Suppose that $a$ is a positive integer for which the least common multiple of $a+1$ and $a-5$ is $10508$. What is $a^2 - 4a + 1$

?
Mathematics
1 answer:
Nana76 [90]3 years ago
4 0

Answer:

21022.

Step-by-step explanation:

Find the prime factors of 10508:

2 ) 10508

2 ) 5254

37 ) 2627

       71.

50208 = 2*2*37*71.

Now there is no integer value for a that would fit  (a+ 1)(a - 5) = 10508 .

But we could try multiplying the LCM by 2:-

= 21016  = 2*2*2*37*71.

= 2*2*37 multiplied by 2 * 71

= 148 * 142.

That looks promising!!

a - 5 = 142 and

a + 1 = 148

This gives  2a - 4 = 290

2a = 294

a = 147.

So substituting a = 147 into a^2 - 4a + 1 we get:

= 21022.

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1 Kg = 2.2046 pounds what will be the answer in round to nearest tenth 4550 pounds = ______ kg
Harrizon [31]

Answer:

2063.9 kg

Step-by-step explanation:

Given,

<u>1 kg = 2.2046 pounds</u>

This can also be written as:

<u>1 pound = 1/2.2046 kg</u>

We have to calculate the value of 4550 pounds in kg up to nearest 10th

Thus,

4550 pounds= \frac{4550}{2.2046} kg

Solving the above equation, we get:

4550 pounds = 2063.8664 kg

Rounding the above result to nearest tenth as:

<u>4550 pounds = 2063.9 kg</u>

6 0
3 years ago
The radius of a circle is 3 5/12 inches <br> What is the diameter of the circle?
nirvana33 [79]

Answer:

6 5/6

Step-by-step explanation:

diameter is radius multiplied by 2

* means multiplied by

3 5/12 = 41/12

41/12 * 2 = 82/12 = 6 5/6

8 0
2 years ago
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10 to the power of 3 times what equals 630
vekshin1
10³ · x = 630
x = ?

10³ = 10 × 10 × 10 = 1,000

630 ÷ 1000 = x
630 ÷ 1000 = 0.63
x = 0.63

So we have:

10³ · 0.63 = 630
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2^2+b^2=12^2
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7 0
3 years ago
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If R is the midpoint of QS, RS=2X-4, ST=4X-1, and RT=8X-43, find QS
Cloud [144]
RT = RS + ST
8x - 43 = 2x - 4 + 4x - 1
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x = 38/2
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QS = 2RS = 2(2x-4) = 2(2*19-4) = 2*34 = 68
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3 years ago
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