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liraira [26]
3 years ago
11

Linear System Word Problem - Animals

Mathematics
1 answer:
Margaret [11]3 years ago
4 0

Answer:

There were 15 birds at the shelter on Monday

Step-by-step explanation: 15 birds x 5$ =75$ and 8 cats x 6$=48$ 75$ + 48$=123$  


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Convert 67 sq ft to sq in
lianna [129]
67*12=804
804 inches=67 feet
4 0
3 years ago
The average daily volume of a computer stock in 2011 was μ=35.1 million​ shares, according to a reliable source. A stock analyst
alexandr1967 [171]

Answer:

The 95% confidence interval is ( 27.126 , 34.674)

Step-by-step explanation:

Given

The t critical value at 0.05 level = 2.023 for the df = 39

Confidence interval = 95%

Mean  

\bar{x} - t * \frac{s}{\sqrt{n} } < \mu < \bar{x} + t * \frac{s}{\sqrt{n} }

Substituting the given values we get -

\30.9 - 2.023 * \frac{11.8}{\sqrt{40} } < \mu < \30.9 + 2.023 * \frac{11.8}{\sqrt{40} }\\27.126 < \mu < 34.674

Hence, the 95% confidence interval is

( 27.126 , 34.674)

4 0
3 years ago
a roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decora
irinina [24]

Answer: The mass of each passenger is 550 kg.

The mass of front decoration = 200 Kg.

Step-by-step explanation:

Let the mass of each passenger be 'x'.

Let the mass of front decoration be 'y'.

So, Number of passenger = 6

Mass of 6 passengers and front decoration = 3500 kg.

Number of passengers = 4

Mass of 4 passengers and front decoration = 2400 kg.

According to question, it becomes,

6x+y=3500\\\\\implies y=3500-6x----------------(1)\\\\4x+y=2400\\\\\implies y=2400-4x---------------(2)

so, From Eq(1) and Eq(2), we have,

3500-6x=y=2400-4x\\\\3500-6x=2400-4x\\\\3500-2400=-4x+6x\\\\1100=2x\\\\x=\frac{1100}{2}=550

Hence, the mass of each passenger is 550 kg.

The mass of front decoration = 3500-550(6)=200 Kg.

6 0
3 years ago
Find the cost of a $19,500 car plus a 6% sales tax
Scrat [10]
There are 2 ways to do this...

19,500(1.06) = 20,670

or

19,500 + 0.06(19,500) = 19,500 + 1170 = 20670
8 0
3 years ago
At murky middle school 372 students participate in sports if this is 60% then how many students go to the school
laiz [17]

divide number of students in sports by percentage:

372 / 0.60 = 620 total students in the school

6 0
3 years ago
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