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Alex
3 years ago
5

Mya and ERIC WORK IN A BAKERY . MYA HAS 3 TIMEA AS MUCH FLOUR AS ERIC .MYA HAS 15.81LB OF FLOUR .USE THE EQUATION 3F = 15.81 TO

FIND HOW MUCH FLOUR ERIC HAS .
Mathematics
1 answer:
Pavel [41]3 years ago
4 0

Answer:

5.27 lb

Step-by-step explanation:

Given that,

Mya has 3 times as much floor as Eric. Mya has 15.81 lb of floor. The relation is given by :

Let Eric has F floor.

3F = 15.81 ...(1)

We need to find how much flour Eric has.

Dividing both sides by 15.81.

F = 15.81/3

F = 5.27 lb

Hence, Eric has 5.27 lb of flour.

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Elanso [62]

3/7= 0.428571

3/6= 0.5

3/5= 0.6

So 3/5 is the greatest of all of them.

8 0
3 years ago
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What is the formula for the following arithmetic sequence? -9 , -2 , 5 , 12
nirvana33 [79]
First term:  -9
Common difference:  7


a(n) = -9 + 7(n-1), for n = {1, 2, 3, ... }

Check:  what is the first term?  let n=1.   Then a(1) = -9 + 7(1-1) = -9.  
This is correct.
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3 years ago
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Need help ASAP! (Geometry 1)
melisa1 [442]

Answer:

The Length of third side is 52 units.

Step-by-step explanation:

Given:

Length of First side = 48

Length of second side = 20

Also given the angle between them is 90°.

Hence we can say figure shown is a right angled triangle.

For finding the third side we can use Pythagoras theorem which states that;

"If a triangle is right angled then, the Square of the hypotenuse is equal to sum of the square of the other two sides."

Third \ side ^2=First \ side^2+Second \ side^2

Hence substituting the values we get;

Third\ side^2= 48^2+20^2 = 2304+400 =2704

Now taking Square root on both side we get;

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3 0
3 years ago
1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
3 years ago
Find the area and perimeter of the rectangle whose sides are lengths 2x + 3 and 4x.
mote1985 [20]

The answer to this problem is 3(2x+1)

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