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3 years ago

Judges in a diving competition gave scores of 9.3, 9 1/2, 9 4/5, 9.95 And 9 1/4. Which two scores were closest to one another?

Mathematics

2 answers:

Sav [38]3 years ago

7 0

9.3 and and 9 1/4 because 9 1/4 is equal to 9.25 and that's only .05 away.

Kazeer [188]3 years ago

6 0

9.3 and $9\frac{1}{4}$ were closest to another.

<u><em>Explanation</em></u>

First we will convert each given fractions into decimal form. So....

$9\frac{1}{2}= 9+\frac{1}{2} = 9+0.50 =9.50\\ \\ 9\frac{4}{5}= 9+ \frac{4}{5}= 9+0.80=9.80\\ \\ 9\frac{1}{4}= 9+\frac{1}{4} =9+0.25= 9.25$

Then the scores are: 9.30, 9.50, 9.80, 9.95 and 9.25

So, 9.30 and 9.25 are closest to another as their difference is (9.30-9.25)=0.05

That means , 9.3 and $9\frac{1}{4}$ were closest to another.

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<h2>Answer:</h2>

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<h3>Cross out the common factor</h3>

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<h3>Find the union of solution sets</h3>

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