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umka2103 [35]
3 years ago
5

Judges in a diving competition gave scores of 9.3, 9 1/2, 9 4/5, 9.95 And 9 1/4. Which two scores were closest to one another?

Mathematics
2 answers:
Sav [38]3 years ago
7 0
9.3 and and 9 1/4 because 9 1/4 is equal to 9.25 and that's only .05 away.
Kazeer [188]3 years ago
6 0

9.3 and 9\frac{1}{4} were closest to another.

<u><em>Explanation</em></u>

First we will convert each given fractions into decimal form. So....

9\frac{1}{2}= 9+\frac{1}{2} = 9+0.50 =9.50\\  \\ 9\frac{4}{5}= 9+ \frac{4}{5}= 9+0.80=9.80\\   \\ 9\frac{1}{4}= 9+\frac{1}{4} =9+0.25= 9.25

Then the scores are: 9.30, 9.50, 9.80, 9.95 and 9.25

So, 9.30 and 9.25 are closest to another as their difference is (9.30-9.25)=0.05

That means , 9.3 and 9\frac{1}{4} were closest to another.

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\boxed{\dfrac{y-2}{y+1} = -\dfrac12 e^{3x}}

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y+1 = \dfrac6{2+e^{3x}}

y = \dfrac6{2+e^{3x}} - 1

\boxed{y = \dfrac{4-e^{3x}}{2+e^{3x}}}

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Answer:

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Step-by-step explanation:

is this k12

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