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Allushta [10]
3 years ago
14

Ebru has a standard deck of cards. The deck has 52 total cards and contains 4 suits: hearts, clubs, diamonds, and

Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer:

The two statements provided are correct.

- P(A|B) = P(A), the conditional probability that Ebru selects a 2 given that she has chosen a

spade is equal to the probability that Ebru selects a 2.

- P(B|A) = P(B), the conditional probability that Ebru selects a spade given that she has

chosen a 2 is equal to the probability that Ebru selects a spade.

Step-by-step explanation:

In total, there are 52 cards.

There are 4 suites; hearts, clubs, diamonds, and spades.

Meaning there are

13 hearts, 13 clubs, 13 diamonds and 13 spades.

Each suit contains cards numbered 2 – 10, a jack, a queen, a king, and an ace.

Let A be the event that the card is a 2 and B be the event that it is a spade.

P(A) = n(cards that are 2s) ÷ n (total)

P(A) = (4/52) = (1/13)

P(B) = n(spades) ÷ n(total)

P(B) = (13/52) = (1/4)

The conditional probability, P(A|B) is given as

P(A|B) = P(A n B) ÷ P(B)

For this cards question,

P(A n B) = n(a spade that is a 2) ÷ n(total)

P(A n B) = (1/52)

So, to investigate,

P(A|B) = P(A), the conditional probability that Ebru selects a 2 given that she has chosen a

spade is equal to the probability that Ebru selects a 2.

P(A|B) = P(A n B) ÷ P(B) = (1/52) ÷ (1/4) = (1/13) = P(A)

Hence, this statement is true!

P(B|A) = P(B), the conditional probability that Ebru selects a spade given that she has

chosen a 2 is equal to the probability that Ebru selects a spade.

P(B|A) = P(B n A) ÷ P(A) = (1/52) ÷ (1/13) = (1/4) = P(B)

This statement is also true!

Hope this Helps!!!

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How many ml of a 20% acid mixture and a 80% acid mixture should be mixed to get 120ml of a 35% acid mixture?
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Answer:

Volume of Mixture A =90 ml

Volume of Mixture B =30 ml

Step-by-step explanation:

Let say, Mixture A + Mixture B = Mixture C

Volume of Mixture A is x

Volume of Mixture B is y

So, Volume of Mixture C is x+y = 120 ml

Now, Acid contain in Mixture A is 20% =0.2x

Acid contain in Mixture B is 80% =0.8y

Also, Acid contain in Mixture C is 35% =(0.35)(x+y) = 0.35×120=42

Now, we know that,

Acid contain of Mixture A + Acid contain of Mixture B=Acid contain of Mixture C

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∴ 2x+8y=420

We get two linear equations

2x+8y=420 and x+y = 120

Solving above equation...

∴ x=120-y

Replacing x value in 2x+8y=420

∴ 2(120-y)+8y=420

∴ 240-2y+8y=420

∴ 6y=180

∴ y=30

Replacing y value in any equation

∴ x=120-y=120-30=90

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Volume of Mixture A is x=90 ml

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Freee pointsss iggg :)
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Yayyy thanks a lottt can i also get brainliest
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