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3 years ago

If triangle ABC has sides of lengths 6,10,and x, between which two numbers must the value of x lie

1 answer:

4 0

The sum of two sides of a triangle must be more than the length of the third side. 6+4 = 10 so x must be greater than 4. 6 + 10 = 16, so x must be less than 16
4<x<16
x is between 4 and 16.

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Compare adding unlike fractions and adding like fractions

muminat

Answer:

We just add numerators and rewrite denominator.

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

Step-by-step explanation:

You mean unlike denominators and like denominators.

Adding like dominators: We just add numerators and rewrite denominator :

Example : $\frac{1}{4} +\frac{2}{4}=\frac{1+2}{4} =\frac{3}{4}$

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

For example :

$\frac{1}{5}+\frac{3}{4}$

LCM for 5 and 4 is 20 : Now, divide by 5 and multiply by 1 for first fraction. 20 divide by 4 and multiply by 3 :

$\frac{1*4}{20} +\frac{3*5}{20}=\frac{4}{20} +\frac{15}{20}=\frac{19}{20}$

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2 years ago

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Step-by-step explanation:

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