If triangle ABC has sides of lengths 6,10,and x, between which two numbers must the value of x lie

1 answer:

4 0

The sum of two sides of a triangle must be more than the length of the third side. 6+4 = 10 so x must be greater than 4. 6 + 10 = 16, so x must be less than 16
4<x<16
x is between 4 and 16.

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