Answer:
length is 20 and the width is 5
Step-by-step explanation:
so Area is 100
Area = width * length
legth = 4 * width
This means:
Area = width * 4 width => Area = 5 * width
We know that area is 100 so:
100 = 5 * width
that means width = 20, but wait didn't I say that the length is 20? Yes, remember we said length = 4 * width at the beginning, so <u>length = 20</u>.
Now we can easily calculate width as width is 4 times smaller than length, so:
<u>width = 20/4 => 5</u>
We can also test if this is correct by simply using the formula to calculate rectangle. So 5 * 20 = 100, correct!
Answer:
(5,0) and (0,3) have a slope of -3/5
Step-by-step explanation:
Here, we want to state a pair of points that have a slope of -3/5
Mathematically, we can have the slope of a straight line calculated as;
m = y2-y1/(x2-x1)
This could give points like (5,0) and (0,3)
Answer:
27.2 ft
Step-by-step explanation:
Since 1 in on the drawing = 8 ft, we should find out how much ft is 3.4 in.
So, to get from 1 to 8, we multiply by 8.
And since we multiply by 8, we also have to do it to the other part as well.
So we would do:
8 x 3.4 = 27.2
Hope this helps! :)
Answer:
r= C over 2π
Step-by-step explanation:
C = 2πr
To solve for r, divide each side by 2π
C/ 2π = 2πr/ 2π
C/ 2π = r
Answer:
Step-by-step explanation:
step 1
Find the measure of the arc DC
we know that
The inscribed angle measures half of the arc comprising
![m\angle DBC=\frac{1}{2}[arc\ DC]](https://tex.z-dn.net/?f=m%5Cangle%20DBC%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20DC%5D)
substitute the values
![60\°=\frac{1}{2}[arc\ DC]](https://tex.z-dn.net/?f=60%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20DC%5D)
step 2
Find the measure of arc BC
we know that
----> because the diameter BD divide the circle into two equal parts
step 3
Find the measure of angle BDC
we know that
The inscribed angle measures half of the arc comprising
![m\angle BDC=\frac{1}{2}[arc\ BC]](https://tex.z-dn.net/?f=m%5Cangle%20BDC%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20BC%5D)
substitute the values
![m\angle BDC=\frac{1}{2}[60\°]](https://tex.z-dn.net/?f=m%5Cangle%20BDC%3D%5Cfrac%7B1%7D%7B2%7D%5B60%5C%C2%B0%5D)
therefore
The triangle DBC is a right triangle ---> 60°-30°-90°
step 4
Find the measure of BC
we know that
In the right triangle DBC
substitute the values
