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3 years ago

Given the function definition below, what is the effect of thecall:

Computers and Technology

2 answers:

Romashka-Z-Leto [24]3 years ago

8 0

Answer:

Hi!

The correct answer is E.

Explanation:

void change(int ar[], int low, inthigh) {

int temp;

if(low< high) { // here ask if the positions low and high of the array are the same.

temp= ar[low]; // first, saves the element on ar[low] in temp.

ar[low]= ar[high]; // second, the element on ar[high] in ar[low]. First switch.

ar[high]= temp; // third, saves the element on temp in ar[high]. Complete switch.

change(ar,low + 1, high - 1); // Recursive call, adding one position to low, and subtracting one position to high. Important: When low and high have the same value, the recursive call will finish.

}

Result: Switch the lower half of elements in the array with the upper half.

Cloud [144]3 years ago

4 0

Answer:

The correct answer is E.

Explanation:

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Using the computational language C++ it is possible to write a code is possible to create a function that stores items like this:

<h3>Writting the code in C++: </h3>

//Header files

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

//Class inventoryItem

class inventoryItem

{

public:

//Variable declaration

string itemName;

string itemNumber;

double itemPrice;

int itemQuantity;

};

//implementation of menuItems() function.

void menuItems()

{

// Display the Menu

cout << "=============================\n";

cout << " 1) Add an item to memory\n"

<< " 2) Search memory for an item \n"

<< " 3) List what's in memory\n"

<< " 4) Total value on hand\n"

<< " 5) Save to a file\n"

<< " 6) Read from a file\n"

<< " 0) Exit Program" << endl;

}

//main method.

int main()

{

//variable declaration.

int mnuChoice, cn = 0, d;

string n;

double sum = 0, c;

int temp;

string a, b;

string inputBuffer;

inventoryItem items[100];

ifstream inventoryFile("inventory.txt");

if (inventoryFile)

{

//store the data from the file to memory.

while (!(inventoryFile.eof()))

{

inventoryFile >> items[cn].itemName;

inventoryFile >> items[cn].itemNumber;

inventoryFile >> inputBuffer;

items[cn].itemPrice = atof(inputBuffer.c_str());

inventoryFile >> inputBuffer;

items[cn].itemQuantity = atoi(inputBuffer.c_str());

cn++;

}

inventoryFile.close();

ifstream inventoryFile("inventory.txt");

ofstream fout;

fout.open("inventory.txt");

do

{

menuItems();

cout << cn << " items stored." << endl;

// Prompt and read choice form the user

cout << "Enter your choice: ";

cin >> mnuChoice;

switch (mnuChoice)

{

//Add a new inventory item to the data in memory.

case 1:

// Prompt and read name of the item from the user

cout << "Enter name of the item: ";

cin >> inputBuffer;

items[cn].itemName = inputBuffer;

// Prompt and read itemNumber from the user

cout << "Enter the itemNumber: ";

cin >> inputBuffer;

items[cn].itemNumber = inputBuffer;

// Prompt and read itemPrice from the user

cout << "Enter the itemPrice: ";

cin >> inputBuffer;

items[cn].itemPrice = atof(inputBuffer.c_str());

// Prompt and read itemQuantity from the user

cout << "Enter the itemQuantity: ";

cin >> inputBuffer;

items[cn].itemQuantity = atoi(inputBuffer.c_str());

cn++;

break;

//Search the inventory for an item by inventory number.

case 2:

temp = 0;

cout << "Enter inventory itemNumber: ";

cin >> n;

for (int i = 0; i < cn&&temp != 1; i++)

{

// If found, print the stored info

if (items[i].itemNumber.compare(n) == 0)

{

// Display the stored information

cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;

cout << items[i].itemName << "\t " << items[i].itemNumber << " \t" << items[i].itemPrice << "\t " << items[i].itemQuantity << endl;

temp = 1;

}

// otherwise print 'not found'.

if (temp == 0)

{

cout << "Not found!!!" << endl;

}

break;

//List the inventory on the screen

case 3:

cout << "The data in the memory is:" << endl;

cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;

for (int i = 0; i < cn; i++)

{

cout << items[i].itemName << "\t " << items[i].itemNumber << "\t " << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;

}

break;

// Calculate the total value on hand.

case 4:

for (int i = 0; i < cn; i++)

{

// The sum is the accumulation of all the (quantities * prices).

sum += items[i].itemPrice*items[i].itemQuantity;

}

cout << "sum value on hand: " << sum << endl;

break;

// Save the inventory data in the given file

case 5:

for (int i = 0; i < cn; i++)

{

if (i == cn - 1)

{

fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity;

}

else

{

fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;

}

break;

// Read the data from the file

case 6:

while (!(inventoryFile.eof()))

{

inventoryFile >> a;

inventoryFile >> b;

inventoryFile >> inputBuffer;

c = atof(inputBuffer.c_str());

inventoryFile >> inputBuffer;

d = atoi(inputBuffer.c_str());

// Dsiplays the data in the file

cout << a << " " <

}

break;

}

// Check the menu choice is not equal to 0,

//if it is equal exit from the loop

} while (mnuChoice != 0);

// File closed

fout.close();

inventoryFile.close();

}

// If the inventory file does not exist

// and then display the error message.

else

{

cout << "File does not exist!" << endl;

}

return 0;

}

See more about C++ code at brainly.com/question/17544466

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5 0

2 years ago