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kicyunya [14]
4 years ago
7

(4/3 • y 2/3) ^ -1/2 = ( y^2) ^ -1/2=

Mathematics
1 answer:
pshichka [43]4 years ago
6 0

Answer:

The answer to that would be 8/9

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Anyone know the area of the blue area?
Studentka2010 [4]
First, find the area of the larger sector (the 360-130=230 degree sector), then add the area of the triangle.
area of the larger sector:(230/360)π*11.1²≈247.17
area of the triangle when two sides and the angle between the two sides are given: (absinФ)/2. In this case, a=11.1, b=11.1, Ф=130
(11.1*11.1*sin130)/2≈47.19
the total area is 247.17+47.19≈294.4
Please use your calculator to double check my numbers.
4 0
4 years ago
) John paints 160 square feet in 45 minutes. How many square feet does he paint in 2 hours
Nataly_w [17]

Answer: 891000

Step-by-step explanation:

6 0
3 years ago
What two ratios form a proportion? A 4/20 and 1/5 B. 4/20 and 2/5 C. 20/4 and 1/5 D. 20/4 and 2/5
Stels [109]

Answer:

A

Step-by-step explanation:

\frac{4}{20} ← divide numerator/ denominator by 4

= \frac{1}{5}

Thus A form a proportion

\frac{4}{20} ≠ \frac{2}{5}

Thus B is not a proportion

\frac{20}{4} ← divide numerator/ denominator by 4

= \frac{5}{1} ≠ \frac{1}{5}

Thus C is not a proportion

\frac{20}{4} ≠ \frac{2}{5}

Thus D is not a proportion

5 0
4 years ago
Read 2 more answers
The u.s. department of health and human services collected sample data for 772 males between the ages of 18 and 24. that sample
soldier1979 [14.2K]
The 99% confidence interval for the true mean is given by:

\bar{x}\pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

where: 

\bar{x} is the sample mean = 69.7
\sigma is the standard deviation = 2.8
z_{\alpha/2} is the test statistics = 2.58 for for 99% confidentce interval.
n is the sample size = 772.

Therefore, the 99% confidence interval is:

69.7\pm2.58\left( \frac{2.8}{\sqrt{772}} \right)=69.7\pm2.58(0.1008) \\  \\ =69.7-0.26\leq\mu\leq69.7+0.26 \\  \\ =69.44\leq\mu\leq69.96
6 0
3 years ago
Read 2 more answers
The equation ​ yˆ=−0.37x2+6.15x+52.3 ​ approximates the average temperature in October in degrees Fahrenheit at an agricultural
sweet-ann [11.9K]

Answer:

The best estimate for the average temperature in October at 10 a.m. is 73.8 degrees Fahrenheit.

Solution:

Number of hours after 5 a.m.: x

At 10 a.m.→x=10-5→x=5

​ yˆ=−0.37(5)^2+6.15(5)+52.3

yˆ=−0.37(25)+30.75+52.3

yˆ=−9.25+30.75+52.3

yˆ=73.8

Answer: The best estimate for the average temperature in October at 10 a.m. is 73.8 degrees Fahrenheit.

4 0
3 years ago
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