A rectangle has a perimeter of 58 inches. The length is five more than twice the width. Write and solve an equation to determine
the width of the rectangle
1 answer:
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the given figure is a rhombus, so it's area =
where, d1 and d2 are diagonals of the rhombus,
and since, the diagnonals of rhombus bisects each other, the values of their diagonals are
(2 × x) and (2 × 15) =》2x and 30 respectively,
so, by finding the area using the given diagonals and equating it with the real area, we get :
=》
=》
=》
=》
so,
value of x = 10 units