The answer fam is........ D)
There are different variations in population size. The best reason why the simulation of the sampling distribution is not approximately normal is that The sample size was not sufficiently large.
<h3>What takes place if a sample size is not big enough?
</h3>
- When a sample size taken by a person or a researcher is not big or inadequate for the alpha level and also analyses that one have chosen to do, it will limit the study statistical power.
Due to the above, the ability to know a statistical effect in one's sample if the effect are present in the population is greatly reduces.
See full options below
Which of the following would be the best reason why the simulation of the sampling distribution is not approximately normal?
A The samples were not selected at random.
B The sample size was not sufficiently large.
с The population distribution was approximately normal.
D The samples were selected without replacement.
E The sample means were less than the population mean.
Previous question
Learn more about population size from
brainly.com/question/1279360
Answer:
I used the function 1-proportion z-interval on the calculator, where I inputted
- Successes(x) = 64
- Sample size(n) = 593
- Confidence Level(C level) = 0.99
It would result in zInterval_1Prop 64,593,0.99: stat.results, where the values are shown below as:
- Lower bound (CLower) = 0.075105
- Upper bound (CUpper) = 0.140747
- test statistic (p^) = 0.107926
- Margin of error (ME) = 0.032821
Therefore, the 99% confidence interval would be around 0.11 ± 0.03 or range from 0.08 to 0.14.
<em><u>Note: not sure if this is correct</u></em><em> O_o</em>
27.0 g
Explanation:
The density of a substance tells you the mass of exactly one unit of volume of said substance.
In your case, aluminium is said to have a density of
density Al
=
2.70 g
.
cm
−
3
This tells you that every
1 mL
of aluminium has a mass of
2.70 g
.
All you have to do now is use the density of aluminium as a conversion factor to go from cubic centimenters of aluminium to grams
10.0
cm
3
⋅
2.70 g
1
cm
3
=
27.0 g
−−−−−
The answer is rounded to three sig figs.
Answer:
Andy is incorrect
Explanation:
Mike and Andy both read 
of the entire book on Tuesday, and on Wednesday, Mike read 
of the book while Andy only read 
of it. Since the fraction is greater than , that means Mike read a greater amount of the book than Andy, so he is wrong. If you'd like further proof, Mike read 
of the book during Tuesday and Wednesday, while Andy read 
of the book during Tuesday and Wednesday. To compare the two fractions, you need to make sure they have the same denominator. The least common multiple of 6 and 10 is 30, so that's what the denominator is going to be when we compare the fractions. 
, 
. Since the fractions' denominators are the same, we can just compare the numerators. 25 is greater than 21, so Mike read more of the book on Tuesday and Wednesday than Andy did.
