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trasher [3.6K]
3 years ago
13

What are all points between two given points, including the two points? A) angle B) line segment C) parallel lines D) perpendicu

lar line
Mathematics
1 answer:
WINSTONCH [101]3 years ago
7 0
Your answer is b. line segment 
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8. Four people enter their names into a
Lerok [7]

Answer:

The probability that Ang wins  and is given a mug is 0.125.

Step-by-step explanation:

Denote the events as follows:

R = Rob wins

S = Sonja wins

J = Jack wins

A = Ang wins

T =  the winner gets a T-shirt

M = the winner gets a Mug

Since any of the four people could be winner the probability of each person winning is same, i.e.

P (R) = P (S) = P (J) = P (A) = 0.25

There only two prizes to select from.

So, the winning person gets any of the two prizes with probability 0.50.

Consider the tree diagram attached.

Compute the probability that Ang wins  and is given a mug as follows:

P(A\cap M) = P (M|A)\times P (A)\\= 0.50\times 0.25\\=0.125

Thus, the probability that Ang wins  and is given a mug is 0.125.

6 0
4 years ago
Evaluate the line integral by the two following methods. xy dx + x2 dy C is counterclockwise around the rectangle with vertices
Airida [17]

Answer:

25/2

Step-by-step explanation:

Recall that for a parametrized differentiable curve C = (x(t), y(t)) with the parameter t varying on some interval [a, b]

\large \displaystyle\int_{C}[P(x,y)dx+Q(x,y)dy]=\displaystyle\int_{a}^{b}[P(x(t),y(t))x'(t)+Q(x(t),y(t))y'(t)]dt

Where P, Q are scalar functions

We want to compute

\large \displaystyle\int_{C}P(x,y)dx+Q(x,y)dy=\displaystyle\int_{C}xydx+x^2dy

Where C is the rectangle with vertices (0, 0), (5, 0), (5, 1), (0, 1) going counterclockwise.

a) Directly

Let us break down C into 4 paths \large C_1,C_2,C_3,C_4 which represents the sides of the rectangle.

\large C_1 is the line segment from (0,0) to (5,0)

\large C_2 is the line segment from (5,0) to (5,1)

\large C_3 is the line segment from (5,1) to (0,1)

\large C_4 is the line segment from (0,1) to (0,0)

Then

\large \displaystyle\int_{C}=\displaystyle\int_{C_1}+\displaystyle\int_{C_2}+\displaystyle\int_{C_3}+\displaystyle\int_{C_4}

Given 2 points P, Q we can always parametrize the line segment from P to Q with

r(t) = tQ + (1-t)P for 0≤ t≤ 1

Let us compute the first integral. We parametrize \large C_1 as

r(t) = t(5,0)+(1-t)(0,0) = (5t, 0) for 0≤ t≤ 1 and

r'(t) = (5,0) so

\large \displaystyle\int_{C_1}xydx+x^2dy=0

 Now the second integral. We parametrize \large C_2 as

r(t) = t(5,1)+(1-t)(5,0) = (5 , t) for 0≤ t≤ 1 and

r'(t) = (0,1) so

\large \displaystyle\int_{C_2}xydx+x^2dy=\displaystyle\int_{0}^{1}25dt=25

The third integral. We parametrize \large C_3 as

r(t) = t(0,1)+(1-t)(5,1) = (5-5t, 1) for 0≤ t≤ 1 and

r'(t) = (-5,0) so

\large \displaystyle\int_{C_3}xydx+x^2dy=\displaystyle\int_{0}^{1}(5-5t)(-5)dt=-25\displaystyle\int_{0}^{1}dt+25\displaystyle\int_{0}^{1}tdt=\\\\=-25+25/2=-25/2

The fourth integral. We parametrize \large C_4 as

r(t) = t(0,0)+(1-t)(0,1) = (0, 1-t) for 0≤ t≤ 1 and

r'(t) = (0,-1) so

\large \displaystyle\int_{C_4}xydx+x^2dy=0

So

\large \displaystyle\int_{C}xydx+x^2dy=25-25/2=25/2

Now, let us compute the value using Green's theorem.

According with this theorem

\large \displaystyle\int_{C}Pdx+Qdy=\displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx

where A is the interior of the rectangle.

so A={(x,y) |  0≤ x≤ 5,  0≤ y≤ 1}

We have

\large \displaystyle\frac{\partial Q}{\partial x}=2x\\\\\displaystyle\frac{\partial P}{\partial y}=x

so

\large \displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx=\displaystyle\int_{0}^{5}\displaystyle\int_{0}^{1}xdydx=\displaystyle\int_{0}^{5}xdx\displaystyle\int_{0}^{1}dy=25/2

3 0
3 years ago
If one time around the track is 1/4, and I went around 23 times. what are the equation and answer? Please do the equation and in
Eduardwww [97]

Answer:

sweet

Step-by-step explanation:

4 0
3 years ago
Math help please?!?!?<br> I promise just some more then Im done!!
Talja [164]
Your answe would be a>-2 so just plug that in to the line and that will be your answer which is the second one
7 0
3 years ago
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The following data of students weights (in kg) is collected 65 48 52 55 62 58 47 53 65 71 54 62 51 49 54 60 68 53 57 62 59​
tatuchka [14]

Answer:

i dont know

Step-by-step explanation:

hynmk,likujnyhbgfd

3 0
3 years ago
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