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GalinKa [24]
3 years ago
13

URGENT A third-grade class has 12 girls and 13 boys. A fourth-grade class has 10 boys and 11 girls. When picking teams for PE, o

ne captain will make a selection from the fourth-grade class, then the other captain will make a selection from the fourth-grade class. After that, the first captain will make a selection from the third-grade class, and the second captain will do likewise. Assuming everyone has an equally likely chance of being selected, what is the probability that the first captain will pick two girls before picking any boys?
A.

44/175


B.

117/143


C.

120/143


D.

133/143
Mathematics
1 answer:
Illusion [34]3 years ago
8 0
A. 44/175 I pretty sure...
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The expression, involving exponents , to represent the shaded area, in square inches, diagram. Then use that expression to calcu
mart [117]

Answer:

The shaded area is 23\ in^{2}

Step-by-step explanation:

we know that

The shaded area is equal to the area of the large square minus the area of the two smaller squares

so

A=6^{2} -(3^{2} +2^{2})\\ \\ A=(2*3)^{2} -(3^{2} +2^{2})\\ \\A=(2^{2})(3^{2}) -(3^{2} +2^{2})

Calculate the shaded area

Remember that

3^{2}=9\\ 2^{2}=4

substitute

A=(4)(9) -(9 +4)\\ \\A=36-13\\ \\A=23\ in^{2}

5 0
3 years ago
It has been estimated that 72.7% of alcoholics need professional help to stop drinking. What is the probability that a random al
Svetradugi [14.3K]

The probability that a random alcoholic can kick the habit without professional help is 0.273 .

<h3>What is Probability ?</h3>

Probability is the study of likeliness of an event to happen.

It has a range of 0 to 1 , where 0 indicates uncertainty and 1 indicates certainty.

It is given that

The alcoholics that need professional help to stop drinking is 72.7 %

Therefore the probability of this is 72.7 /100 = 0.727

The probability that they will not need professional help is given by

q = 1 - p

q = 1 -0.727

q = 0.273

Therefore the probability that a random alcoholic can kick the habit without professional help is 0.273 .

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5 0
2 years ago
The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t
damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that \mu = 3

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498

P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494

P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240

P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240

Then

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

3 0
2 years ago
What is 25/6 times 2
Darya [45]
25/6 converts to 4 1/6 so 
4 1/6 x 2 = 8 1/3 
8 1/3 is your answer :)
6 0
3 years ago
Read 2 more answers
Question 1 (1 point)
bearhunter [10]
It’s is b why u covering your camera lol
4 0
3 years ago
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