How do it write "f divided by the quantity h minus 3" as a fraction

Mathematics

2 answers:

Amanda [17]3 years ago

8 0

I believe f/h-3 is the answer. hope this helps :)

9966 [12]3 years ago

7 0

F/h-3 is the answer. Everytime you see divided it's gonna be a fraction!

You might be interested in

Solve 50q-43=52q-81

ladessa [460]

Move the variables to one side and the constants to the other

50q - 43 = 52q - 81

50q (-52q) - 43 (+43) = 52q (-52q) - 81 (+43)

50q - 52q = -81 + 43

-2q = -38

isolate the q, divide -2 from both sides

-2q/-2 = -38/-2

q = -38/-2

q = 19

hope this helps

8 0

3 years ago

Read 2 more answers

What is the volume of the cone ?

sleet_krkn [62]

${210in}^{3}$

This is found by the volume of a cone formula

$b \times \frac{h}{3}$

Where b is the base and h is the height

$45 \times \frac{14}{3} = \frac{630}{210} = 210$

5 0

3 years ago

Evaluate the infinite sum:

satela [25.4K]

Consider the k-th partial sum,

$S_k = 1 + \dfrac2\pi + \dfrac3{\pi^2} + \cdots + \dfrac k{\pi^{k-1}}$

More compactly,

$\displaystyle S_k = \sum_{i=1}^k \frac i{\pi^{i-1}} = \frac{(1-\pi)k+\pi^{k+1}-\pi}{(1-\pi)^2\pi^{k-1}}$

(this is just another case of a similar sum you asked about a while ago [24494877])

The infinite sum is the limit of the partial sum as k goes to infinity. We have

$\displaystyle \lim_{k\to\infty} \frac{(1-\pi)k+\pi^{k+1}-\pi}{(1-\pi)^2\pi^{k-1}} = \frac\pi{(1-\pi)^2} \lim_{k\to\infty} \left(\frac{(1-\pi)k}{\pi^k} + \pi - \frac1{\pi^{k-1}} \right) = \boxed{\frac{\pi^2}{(1-\pi)^2}}$