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Vedmedyk [2.9K]
3 years ago
13

What is the X and Y intercept of 8(4+x)-3=12(x+y)+5

Mathematics
1 answer:
Zanzabum3 years ago
5 0
Lets get this into y-intercept form first, which is y =mx+b:

8(4+x)-3 = 12(x+y)+5

32+8x-3 = 12x+12y+5

-4x+24 = 12y

-1/3x+2 = y or y= -1/3x + 2

X intercept: 
0 = -1/3x + 2
-2= -1/3x
6 = x

X intercept is (6,0)

Y intercept:
y = -1/3(0) + 2
y= 2

Y intercept is (0,2)

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paul paid $2.80 each,wholesale for 200 novelty memory sticks.he marked up the price 90%. find the selling price.
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He bought 200 of them
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The comeplement of 99
harkovskaia [24]
1. the complement is when two angles add up to 99 degrees and the supplement is when the two angles add up to 180 degrees.

2. Let x be the measure of the unknown angle .

3. Let 90 -x be it's complement and 180- x be the supplement of the angle .

4. Given 90-x=3x+9 the measure of the complement of an angle is 3x+9. Solve using the following steps.

99-x=3x+9
Add x-9 to both sides to isolate x-terms on right side and numbers on left
90-x+x-9=3x+9+x-9

90-x+x-9=3x+9+x-9

91=4x
divide by 4 to both sides yields
91/4=x

5. Given 3x+99=180-x. The measure of the supplement of an angle is 3x+99. So
3x+99=180-x

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3x+99+x-99=180-x+x-99

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3 0
3 years ago
Estimates 3 2/3 \ 3 2/9
IrinaK [193]
Hello  
<span>3 2/3 \ 3 2/9
(32/3) × (9/32) = 9/3=3</span>
6 0
3 years ago
The length of a rectangle is 5 ft less than three times the width, and the area of the rectangle is 50 ft². Find the dimensions
Mariulka [41]

Answer

Length = 10 ft

Width = 5 ft

Explanation

Area of the rectangle given = 50 ft²

Let the width of the rectangle be x

So this means the length of the rectangle will be 3x - 5

What to find:

The dimensions of the rectangle.

Step-by-step solution:

Area of a rectangle = length x width

i.e A = L x W

Put A = 50, L = 3x - 5, W = x into the formula.

\begin{gathered} 50=(3x-5)x \\ 50=3x^2-5x \\ 3x^2-5x-50=0 \end{gathered}

The quadratic equation can now be solve using factorization method:

\begin{gathered} 3x^2-5x-50=0 \\ 3x^2-15x+10x-50=0 \\ 3x(x-5)+10(x-5)=0 \\ (3x+10)(x-5)=0 \\ 3x+10=0\text{ }or\text{ }x-5=0 \\ 3x=-10\text{ }or\text{ }x=5 \\ x=-\frac{10}{3}\text{ }or\text{ }x=5 \end{gathered}

Since the dimension can not be negative, hence the value of x will be = 5.

Therefore, the dimensions of the rectangle will be:

\begin{gathered} Length=3x-5=3(5)-5=15-5=10\text{ }ft \\  \\ Width=x=5\text{ }ft \end{gathered}

7 0
1 year ago
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