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castortr0y [4]
3 years ago
9

What's 2x+3y=6 and x-3y=9?

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
Set up a system of equations:

2x+3y=6
x-3y=9

You can solve this with elimination by adding the two equations together:

3x+0y = 15
3x=15
x=5

Then, plug this value back into either of the original equations to find the y value:

5-3y=9
-3y=4
y= -4/3

The point of intersection is (5,-4/3)
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Your answer would be -16.
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3 years ago
Convert (2, π) to rectangular form
blagie [28]

Answer: 0 . x=2⋅0.

Hope this helps!

3 0
2 years ago
Help me plz I’ve never been good with math
S_A_V [24]
Its 16.

So you have 12 miles on that trail, and markers every 2/3 of the way there. If you were to divide 2 with 3 then you can get the decimal of the fraction. Which in this case it’s 0.75. So every single 0.75 of the mile there is a marker. Divide 12 with 0.75 and you get 16 markers.


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4 0
3 years ago
An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up
Papessa [141]

Answer:

s(t)=-9.8t^2+49t+58.8

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form s(t)=-gt^2+v_0t+h_0, where

g = Force of gravity,

v_0 = Initial velocity,

h_0 = Initial height.

For our given scenario g=-9.8, v_0=49 and h_0=58.8. Upon substituting these values in object's height function, we will get:

s(t)=-9.8t^2+49t+58.8

Therefore, the function for the height of the arrow would be s(t)=-9.8t^2+49t+58.8.

6 0
3 years ago
Write functions for each of the following transformations using function notation. Choose a different letter to represent each f
kupik [55]

Answer:

(a)\ T_{a,b} =(x +a,y+b)

(b)\ F_{y\ axis} = (-x,y)

(c)\ F_{x\ axis} = (x,-y)

(d)\ R_{o,90^o} = (-y,x)

(e)\ R_{o,180^o} = (-x,-y)

(f)\ R_{o,270^o} = (y,-x)

Step-by-step explanation:

Solving (a): Translate a units right, b units up

When a function is translated a units right, the number of units will be added to the x coordinate

When a function is translated b units up, the number of units will be added to the y coordinate.

So, we have:

T_{a,b} =(x +a,y+b)

Solving (b): Reflect across y-axis

When a function is translated across the y-axis, the x coordinate gets negated.

So, we have:

F_{y\ axis} = (-x,y)

Solving (c): Reflect across x-axis

When a function is translated across the x-axis, the y coordinate gets negated.

So, we have:

F_{x\ axis} = (x,-y)

Solving (d): 90 degrees rotation counterclockwise

When a function is rotated 90 degrees counterclockwise, the y-coordinates gets negated and then swapped with the x-coordinate.

So, we have:

R_{o,90^o} = (-y,x)

Solving (e): 180 degrees rotation counterclockwise

When a function is rotated 180 degrees counterclockwise, the coordinates are negated.

So, we have:

R_{o,180^o} = (-x,-y)

Solving (f): 270 degrees rotation counterclockwise

When a function is rotated 270 degrees counterclockwise, the x-coordinates gets negated and then swapped with the y-coordinate.

So, we have:

R_{o,270^o} = (y,-x)

6 0
3 years ago
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