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AveGali [126]
3 years ago
8

Pa sagot po ty po sa sasagot ​

Mathematics
1 answer:
vesna_86 [32]3 years ago
4 0

Answer:

An account-ant

Step-by-step explanation:

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The vertices of a triangle are P(−3, −4), Q(3, 4), and R(−6, −3). Name the vertices of Rx = 0 (PQR).
Katyanochek1 [597]
The correct answer is <span>A) P'(3, −4), Q'(−3, 4), R'(6, −3)</span>

Rx = 0 indicates a reflection over the y-axis. 

The rule for such a transformation is:
(x, y) --> (-x, y)
which means that the x-coordinate changes sign and the y-coordinate stays the same.

Therefore:
P<span>(-3, -4) --> P'(3, -4)
Q(3, 4) --> Q'(-3, 4)
R(-6, -3)</span> --> R'(6, -3)

These points are those in option A).
6 0
3 years ago
write the following inequality in slope-intercept form. –6x 2y ≤ 42 a. y ≥ 3x 21 b. y ≤ 3x – 21 c. y ≥ 3x – 21 d. y ≤ 3x 21
borishaifa [10]
-6x + 2y =< 42
2y =< 6x + 42
y =< 3x + 21
4 0
3 years ago
Read 2 more answers
Sorry for tabs!! I need help in this. Please help me.
telo118 [61]

Answer: 11 more i think

Step-by-step explanation:

8 0
3 years ago
The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va
Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore

4 0
3 years ago
Please need help the review with my quiz on Thursday
eduard

Answer:

ubpg

Step-by-step explanation:

7 0
3 years ago
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