It is described as relatively non specific
Answer:
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Explanation:
These pathogens include, but are not limited to, hepatitis B virus (HBV) and ... Contaminated Laundry means laundry which has been soiled with blood or other ... (3) Any other procedure involving the potential for occupational exposure to ... Food and drink shall not be kept in refrigerators, freezers, shelves, cabinets
The correct answer is d.
Carbohydrates are a very important part of an athlete's diet, since they provide the necessary energy for competition and endurance, but also help in the process of muscle gain.
The amount of carbohydrates that Shana should consume depend heavily on the intensity of her exercise activities. For a moderate level of exercise, which equals to 1 hour of exercise daily, a person should consume 5-7 g/kg of body weight. For a high level of exercise (1-3 hours of daily exercise), a person should consume 6-10 g/kg.
Guessing that Shana will perform a high level of exercise and based on her weight (135 lb or 61.2 kg), Shana should consume 366 to 610 g of carbohydrates daily.
Answer:
Intestinal blood flow is critical for digestion, as well as being a key element of overall ... The O2 consumption of the small intestine is more rigorously controlled than is the ... Much less commonly, water and solutes move slowly by pinocytosis.
Explanation:
Answer:
Parental genotypes: RrBb, RRBB
Offspring phenotype: Running and black hair
Explanation:
Given, Running (R) is dominant over waltzing (r)
Black hair (B) is dominant over brown hair (b)
Parent 1: Heterozygous running, heterozygous black = RrBb
Parent 2: Homozygous running, homozygous black = RRBB
When they mate ( RrBb X RRBB ) :
Gametes produced by RrBb = RB, Rb, rB, rb
Gametes produced by RRBB = RB
Offspring:
RB Rb rB rb
RB RRBB RRBb RrBB RrBb
All offspring mice will be running mice and will have black hair because all the four types of genotype at least have one dominant allele for both the genes.
