All of the given numbers are both real and rational, and so all of their respective squares are also real and rational.
By the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
<h3>How to find the solution of quadratic equation</h3>
Herein we have a <em>quadratic</em> equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the <em>quadratic</em> formula:
x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c) (1)
If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:
x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]
x = - 6 ± (1 / 2) · 12
x = - 6 ± 6
Then, by the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
To learn more on quadratic equations: brainly.com/question/1863222
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The answer is 440.
What I do is just take the -11 and -15 out of the parentheses so it is -11*-15 and the answer is 165. Then, you take -11 and -25 out of the parentheses and find the answer.
Add them together.
Hope that helped :)
I think the answer is 20 but I'm not sure
