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2 years ago

7, 15, 23, ... Find the 41st term.

Mathematics

1 answer:

Katarina [22]2 years ago

6 0

Answer:

Give one possible reason why is it important to eat fish

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If the difference of a number and four is doubled the result is 1/4 less than the number. find the number

sukhopar [10]

The formula is (2)(n-4) = n-1/4

Mult both sides by 4:

8n - 32 = 4n -1, or 4n = 31, or n=31/4.

If this is not what you expected, please ensure that you have copied down the original problem correctly. What do you mean by "1/4 less?"

Let's try (2)(n-4) = 1n-(1/4)n = (3/4)n. Then,

2n-8 = (3/4)n, or (5/4)n = 8. Mult. both sides by (4/5), we get:

n = (5/4)(8) = 10. Is that what you were hoping for?

8 0

3 years ago

The Arnold family arrived at the beach at

AlekseyPX

Answer:

13:30 military time, 1:30 normal time.

8 0

2 years ago

Read 2 more answers

Joe played the trumpet from 6:30 to 7:05 one day. The next he played from 3:55 to 4:15. How many minutes did he play in two days

VARVARA [1.3K]

Answer:

55 minutes

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the missing dimension of the prism

Andrews [41]

<em>X = 2 cm</em>

Volume = Bh= 8×5×1/2×X= 80

X = 80/20 = 4

6 0

2 years ago

Can you please help me out

Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

$\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}$

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

$\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}$ $\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}$

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

$\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}$

Hence, the best option is G.

5 0

1 year ago