Answer:
<em><u>The</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>C</u></em><em><u> </u></em><em><u>no</u></em>
Explanation:
<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>dear</u></em><em><u> </u></em><em><u /></em>
1.Creativity
2.Leadership
3.Attention to detail
5.Enjoyment to learning new things!
6.Vision
No Problem!
Answer:
A) Malicious Association,
Hope this helps.
Explanation:
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Among the choices above the answer is C which is <span>of government taxation
To complete the sentece "</span>Ultimately, there exists a ceiling on efficiency because of government taxation
Answer: Program for bit stuffing in C
#include<stdio.h>
int main()
{
int i=0,count=0;
char data[50];
printf("Enter the Bits: ");
scanf("%s",data); //entering the bits ie. 0,1
printf("Data Bits Before Bit Stuffing:%s",databits);
printf("\nData Bits After Bit stuffing :");
for(i=0; i<strlen(data); i++)
{
if(data[i]=='1')
count++;
else
count=0;
printf("%c",data[i]);
if(count==4)
{
printf("0");
count=0;
}
}
return 0;
}
Explanation:
bit stuffing is the insertion of non-information bits during transmission of frames between sender and receiver. In the above program we are stuffing 0 bit after 4 consecutive 1's. So to count the number of 1's we have used a count variable. We have used a char array to store the data bits . We use a for loop to iterate through the data bits to stuff a 0 after 4 consecutive 1's.