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evablogger [386]
3 years ago
6

Evquivilent Ratio for 23:37

Mathematics
1 answer:
solong [7]3 years ago
7 0

Answer:

46:74

Step-by-step explanation:

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3 years ago
A shed has dimensions of 12m in length and 5 m in width. Both the length and width are increased by the same amount in order to
mestny [16]

The amount by which the length and width of a shed can be increased to

more than double the area, depends on the initial dimensions.

  • The amount that can be added to both the length and the width to increase the floor area by more than double the original area is more than <u>3 meters</u>.

Reasons:

The given parameters of the shed are;

The length of the shed = 12 m

Width of the shed = 5 m

The amount by which the length and the width are increased = The same amount

The new area after the increase in the length and width of the shed = More than double the initial area

Required:

The amount of increase in the length.

Solution:

Let the amount by which the length and width are increased = x

We have;

Initial area of the shed = 12 m × 5 m = 60 m²

The new area = (12 + x) × (5 + x) > 2 × 60

By multiplication, we get;

(12 + x) × (5 + x) = x² + 17·x + 60 > 2 × 60 = 120

x² + 17·x + 60 - 120 > 120 - 120 = 0

x² + 17·x - 60 > 0

By factorization, we get;

(x + 20)·(x - 3) > 0

x > -20, or x > 3

The increase (positive) amount of the solution is x > 3

Therefore, <u>the amount by which both the length and the width can be increased to more than double the area is x > 3 meters</u>

Learn more about the area of a rectangle here:

brainly.com/question/16410706

7 0
2 years ago
How many students are in the freshman class.
maxonik [38]

Answer:

202

Step-by-step explanation:

SOPH= 262

FRESH= 202

JUNIOR= 354

SENIOR= 606

TOTAL 1424

8 0
3 years ago
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